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bonufazy [111]
3 years ago
5

As more potassium sulfate dissolves in the water, the mixture becomes.. PLEASE HELP ME

Chemistry
2 answers:
igomit [66]3 years ago
6 0

Answer:

the mixture becomes more concentrated

Explanation:

this is due to more solute ions of potassium sulphate than solvent ions of water

Tema [17]3 years ago
4 0

Answer:

it will become heterogenous and as well asit will dissociate into ions

also it will form base and evolve h2gas

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1. Why fractional distillation has<br> fractionating column but not in simple<br> distillation?
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3 years ago
What is the chemical formula for the molecule
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Answer: it’s the third one

Explanation:

4 0
3 years ago
What is the [H3O+] if the [OH-] is 1 x 10 -8?
Tanzania [10]

From the calculation, the concentration of the oxonium ions is 1 * 10^-6 M

<h3>What is concentration?</h3>

The term concentration refers to the amount of substances present in the solution. There are several units that can be used to show the concertation of a substances such as moles/liter, gram per liter, parts per billion, parts per billion, percentage etc.

Now we know that water is composed of the hydrogen and the hydroxide ions and the product of the both is generally known as the ion product of water and have a value of 1 * 10^-14.

If that be the case, we are in order to write the expression;

[H3O+]  [OH-] = 1 * 10^-14

[H3O+] = 1 * 10^-14/ [OH-]

[H3O+] = 1 * 10^-14/ 1 x 10^ -8

[H3O+] = 1 * 10^-6 M

Learn more about concentration:brainly.com/question/10725862

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5 0
2 years ago
What is the empirical formula of a substance that contains 2.64 g of c, 0.444 g of h, and 7.04 g of o?
vitfil [10]

To calculate empirical formula, number of moles of different atoms calculated first:

Number of moles of Carbon , n=  

=\frac{Given mass of carbon}{Molar mass of carbon}

=\frac{2.64 g}{12.011 g mol^{-1}}

= 0.220 mol  

Number of moles H =\frac{Given mass of hydrogen}{Molar mass of hydrogen}

=\frac{0.444 g}{1.008 g mol^{-1}}

= 0.440 mol

Number of moles of oxygen =\frac{Given mass of oxygen}{Molar mass of oxygen}

=\frac{7.04 g}{15.999 g mol^{-1}}

= 0.440 mol

Ratio of carbon

=\frac{0.220}{0.220}

= 1

Ratio of hydrogen

=\frac{0.440}{0.220}

= 2  

Ratio of oxygen

=\frac{0.440}{0.220}

= 2  

So, the empirical formula is CH₂O₂

5 0
4 years ago
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