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meriva
3 years ago
7

Think about a thermos bottle. It consists of an inner bottle with a shiny silver surface separated from an outer container by a

space with no air. In what ways does it block conduction, convection, and radiation?
Physics
1 answer:
Mademuasel [1]3 years ago
7 0

Answer:

Radiation

Explanation:

Conduction, convection and radiation are the three modes of heat transfer.

1. Conduction: When the one end is heated of any rod, the heat transfer to the other end by the vibrational motion of the molecules, it is called conduction.

The heat transfer in a solid is due to the conduction.

2. Convection: When the liquid or gas is heated, the molecules which is in contact to the heat, heated first and due to the decrease in density they moves up and the molecules on the upper side are higher in density so they moves down. These are called convection currents. The process continues till the entire liquid becomes heated. It generally takes place in liquids and gases.  

3. Radiation: The process of heat transfer in which no molecules takes place is called radiation. The heat coming from sun is due to the radiation. It does not require any medium.  

In the thermos bottle, as there is no air between the two layers, so the heat transfer is due to the radiation.  

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An object is swung in a horizontal circle on a length of string that is 0.93 m long. Its acceleration is 26.36 m/s2. What is the
Igoryamba

Answer:

The object takes approximately 1.180 seconds to complete one horizontal circle.  

Explanation:

From statement we know that the object is experimenting an Uniform Circular Motion, in which acceleration (a), measured in meters per square second, is entirely centripetal and is expressed as:

a = \frac{4\pi^{2}\cdot R}{T^{2}} (1)

Where:

T - Period of rotation, measured in seconds.

R - Radius of rotation, measured in meters.

If we know that a = 26.36\,\frac{m}{s^{2}} and R = 0.93\,m, then the time taken by the object to complete one revolution is:

T^{2} = \frac{4\pi^{2}\cdot R}{a}

T = 2\pi\cdot \sqrt{\frac{R}{a} }

T = 2\pi\cdot \sqrt{\frac{0.93\,m}{26.36\,\frac{m}{s^{2}} } }

T \approx 1.180\,s

The object takes approximately 1.180 seconds to complete one horizontal circle.  

7 0
3 years ago
If you want to go to a community college and transfer to a four-year university, what classes are required to transfer? How many
bagirrra123 [75]

Typically, most four-year institutions will require the following classes to transfer:

2 English composition courses.

1 Speech course.

1 Critical thinking course.

1 Physical science class.

1 Biological science class.

1 Health class.

2 Physical education courses.

Completion of college algebra

That's all I think

3 0
4 years ago
In the far future, astronauts travel to the planet Saturn and land on Mimas, one of its 62 moons. Mimas is small compared with t
OverLord2011 [107]

Answer:

a) h = 13,205.4 m

b)  r_f = 2.12 106 m

c)        e% = 0.68%

Explanation:

a) This is an exercise we are asked to use energy conservation,

Starting point. On the surface of Mimas

        Em₀ = K = ½ m v²

Final point. Where the ball stops

       Em_{f} = U = m g h

        Em₀ = Em_{f}

        ½ m v² = m g h

         h = ½ v² / g

let's calculate

         h = ½ 41² / 0.0636

         h = 13,205.4 m

b) For this part we are asked to use the law of universal gravitation, write the energy

starting point. Satellite surface

           Em₀ = K + U = ½ m v² - GmM / r_o

final point. Where the ball stops

            Em_{f}= U = - G mM / r_f

          Em₀ = Em_{f}

          ½ m v² - G m M / r_o = - G mM / r_f

In this case all distances are measured from the center of the satellite

         1 / rf = 1 / GM (-½ v² + G M / r_o)

     

let's calculate

         1 / rf = 1 / (6.67 10⁻¹¹ 3.75 10¹⁹) (- ½ 41 2 + 6.67 10⁻¹¹ 3.75 10¹⁹ / 1.98 105)

         1 / r_f = 3,998 10⁻¹¹(-840.5 + 12.63 10³)

          1 / r_f = 4,714 10⁻⁷

          r_f = 1 / 4,715 10⁻⁷

          r_f = 2.12 106 m

to measure this distance from the satellite surface

          r_f ’= r_f - r_o

          r_f ’= 2.12 106 - 1.98 105

         r_f ’= 1,922 106 m

c) the percentage difference is

          e% = 13 205.4 / 1,922 106 100

          e% = 0.68%

The estimate of part a is a little low

6 0
4 years ago
What is the value of Vo in the
notsponge [240]

Answer: 60m/s

Explanation:

From the diagram:

Θ = 30°

Vertical resolution (y-axis) :

Voy = VoSinΘ

g in the upward direction = negative (-) = - g

Vfinal = 0

Distance (H) traveled along y =

Time taken to reach maximum height :

From v = u + at

0 = usinΘ - gt

gt = usinΘ

t = usinΘ / g

Horizontal resolution:

S = ut + 1/2at^2

Substituting t = usinΘ / g ; Voy = usinΘ

S = (usinΘ × usinΘ / g) - 1/2 g × (usinΘ /g)^2

S = (u^2sin^2Θ / g) - (u^2sin^2Θ / 2g)

S = (u^2sin^2Θ) / 2g

Now if S = maximum height = 45m

Then,

45 = [Vo^2sin^2(30°)] / 2(10)

45 =[ Vo^2 * (0.5)^2] / 20

45 =( Vo^2 * 0.25) / 20

20 * 45 = Vo^2 * 0.25

900 / 0.25 = Vo^2

3600 = Vo^2

Vo = sqrt(3600)

Vo = 60m/s

5 0
3 years ago
Emboldened by the success of their late night keg pull in Exercise 61 above, our intrepid young scholars have decided to pay hom
alexdok [17]

Answer is answer

XD                                ssssss

5 0
3 years ago
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