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olga_2 [115]
3 years ago
5

How are distance and displacement the same?

Physics
2 answers:
Sonja [21]3 years ago
6 0
Distance and displacement are two quantities that may seem to mean the same thing yet have distinctly different definitions and meanings. Distance is a scalar quantity that refers to "how much ground an object has covered" during its motion.
ratelena [41]3 years ago
3 0
In the case of straight line, when the object is not repeating it's path then distance and displacement would be same.
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The equation for gear ratio
Ymorist [56]
In a gear train with two gears, the gear ratio is defined as follows
R= \frac{\omega _A}{\omega _B} 

where \omega _A is the angular velocity of the input gear while \omega _B is the angular velocity of the output gear. 

This can be rewritten as a function of the number of teeth of the gears. In fact, the angular velocity of a gear is inversely proportional to the radius r of the gear:
\omega = \frac{v}{r}
But the radius is proportional to the number of teeth N of the gear. Therefore we can rewrite the gear ratio also as
R= \frac{\omega _A}{\omega _B} = \frac{r_B}{r_A} = \frac{N_B}{N_A}

4 0
3 years ago
In a double-slit experiment, light from two monochromatic light sources passes through the same double slit. The light from the
GaryK [48]

We will determine the wavelength through the relationship given by the distance between slits, this relationship is given under the function

y = \frac{m\lambda}{d}

Here,

m = Number of order bright fringe

\lambda = Wavelength

d = Distance between slits

Both distance are the same, then

y_1 = y_2

\frac{m_1\lambda_1 r}{d} = \frac{m_2\lambda_2 r}{d}

\frac{m_1\lambda_1}{m_2\lambda_2} =1

 Rearranging to find the second wavelength

m_1 \lambda_1 = m_2 \lambda _2

\lambda_2 = \frac{m_1\lambda_1}{m_2}

\lambda_2 = \frac{7(629)}{8}

\lambda_2 = 550.3nm

Therefore the wavelength of the light coming from the second monochromatic light source is 550.3nm

7 0
3 years ago
A distorted 1kHz sine wave is represented by the equation: LaTeX: v(t) = 5sin(2 \pi 1000t) + 0.05sin(2 \pi 3000t)v ( t ) = 5 s i
vovikov84 [41]

Answer:

As given in the problem statement

frequency=1 KHz=1*10^3 Hz

V(t) is represented as

v(t) = 5sin(2 \pi 1000t) + 0.05sin(2 \pi 3000t)

v ( t ) = 5 s i n ( 2 π 1000 t ) + 0.05 s i n ( 2 π 3000 t )

Total harmonic distortion will be 234 Pi

3 0
3 years ago
A cyclotron designed to accelerate protons has a magnetic field of magnitude 0.15 T over a region of radius 7.4 m. The charge on
klio [65]

Explanation:

It is given that,

Magnetic field, B = 0.15 T

Charge on a proton, q=1.60218\times 10^{-19}\ C

Mass of a proton, m=1.67262 \times 10^{-27}\ kg

The cyclotron frequency is given by :

f=\dfrac{qB}{2\pi m}

f=\dfrac{1.60218\times 10^{-19}\ C\times 0.15\ T}{2\pi \times 1.67262 \times 10^{-27}\ kg}

f = 2286785.40 Hz

or

\omega=14368296.44\ rad/s

\omega=1.43\times 10^7 rad/s

Hence, this is the required solution.

8 0
3 years ago
How do you calculate the gravitational force on a rubber ball which has a mass of 50g
AfilCa [17]
P (gravitational force) = m (mass) x g
<=> P = 0.05 x 10
<=> P = 0.5N
6 0
3 years ago
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