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NikAS [45]
3 years ago
9

How would you use the parallelogram method of vector addition when more than two forces are added?

Physics
1 answer:
ipn [44]3 years ago
7 0

Answer:

In order to use the parallelogram method, we have to select first two vectors.  We move the vectors until their initial points coincide. Then we draw lines to form a complete parallelogram, as is shown in the figure annexed. The diagonal from the initial point to the opposite vertex of the parallelogram is the resultant.

We use the last vector resultant with a third vector, and we use again the parallelogram method to add them. We use the new resultant and we add it with a 4th vector. We repeat this task until all the vectors are used.

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Complete this sentence. If the mass of object A is __________ than object B, then the weight of object A will be _______________
AfilCa [17]

Answer:

Complete this sentence. If the mass of object A is greater than object B, then the weight of object A will be heavier the weight of object B.

Explanation:

If the mass of Object A is more/greater than object B then it would be "heavier"

4 0
3 years ago
Read 2 more answers
A 160 g basketball has a 32.7 cm diameter and may be approximated as a thin spherical shell. Starting from rest, how long will i
mafiozo [28]

Answer:

   t = 0.24 s

Explanation:

As seen in the attached diagram, we are going to use dynamics to resolve the problem, so we will be using the equations for the translation and the rotation dyamics:

Translation:  ΣF = ma

Rotation:      ΣM = Iα ; where α = angular acceleration

Because the angular acceleration is equal to the linear acceleration divided by the radius, the rotation equation also can be represented like:

                    ΣM = I(a/R)

Now we are going to resolve and combine these equations.

For translation:     Fx - Ffr = ma

We know that Fx = mgSin27°, so we substitute:

         (1)                 mgSin27° - Ffr = ma  

For rotation:         (Ffr)(R) = (2/3mR²)(a/R)

The radius cancel each other:

        (2)                Ffr = 2/3 ma

We substitute equation (2) in equation (1):

                            mgSin27° - 2/3 ma = ma

                            mgSin27° = ma + 2/3 ma

The mass gets cancelled:

                            gSin27° = 5/3 a

                            a = (3/5)(gSin27°)

                            a = (3/5)(9.8 m/s²(Sin27°))

                            a = 2.67 m/s²

If we assume that the acceleration is a constant we can use the next equation to find the velocity:

                           V = √2ad; where  d = 0.327m

                           V = √2(2.67 m/s²)(0.327m)

                            V = 1.32 m/s

Because V = d/t

                             t = d/V

                             t = 0.327m/1.32 m/s

                             t = 0.24 s

7 0
3 years ago
Length of table is 1.0m,1.00m and 1.000m.Which one is more accurate?​
natita [175]

Answer:

1.00 m is a more accurate measured length.

Explanation:

Denote length of the table by L.

For L=1.0 m, there is one significant digit after the decimal.

Care 1: When one more significant digit after decimal considered, the exact number can be from 0.95 to 1.05.

So, the possible span of error \Delta E_1= 1.05-0.95= 0.1m

For L=1.00 m, there is two significant digits after the decimal.

Case 2: When one more significant digit after decimal considered, the exact number can be from 0.095 to 1.005.

So, the possible span of error \Delta E_2= 1.005-0.095= 0.01m

Case 3: For L=1.000 m, there is three significant digits after the decimal.

When one more significant digit after decimal considered, the exact number can be from 0.0095 to 1.0005.

So, the possible span of error \Delta E_3= 1.0005-0.0095= 0.001m

As \Delta E_1 >\Delta E_2>\Delta E_3

So, the least error is in the third case when L=1.00m, hence, L= 1.00m is more accurate.

6 0
3 years ago
The farther you bring charged objects​
stiks02 [169]

Answer:

Weaker, stronger

Explanation:

hope this helped!

3 0
3 years ago
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How long does it take a car to go 1000 m if it is going at 50 m/sec?
Lina20 [59]

The car would take 20 seconds to go 1000 meters. This can be found by dividing 1000 by 50.

If you need more help, comment below and I will be happy to assist.

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