I am pretty sure it is density
Answer:
5.59x10^-3 moles
Explanation:
The balanced equation for the reaction is given below:
HCl + KOH —> KCl + H2O
Now we can obtain the number of mole of HCl required to produce 5.59x10^-3 moles of KCl as follow:
From the balanced equation above, 1 mole of HCl produced 1 mole of KCl.
Therefore, 5.59x10^-3 moles of HCl will also produce 5.59x10^-3 moles of KCl.
From the illustration made above, we can see evidently that 5.59x10^-3 moles of HCl is required to produce 5.59x10^-3 moles of KCl
The most common hydrogen carbon fuels are ethanol and diesel and their product of combustion is carbon dioxide, water and heat .
Answer:
First of all we will calculate the amount of CO₂ produced by burning 10 grams of Methane. The balance chemical equation is as follow:
CH₄ + 2 O₂ → CO₂ + 2 H₂O
First we will calculate the moles of CH₄ as,
Moles = Mass / M.Mass
Moles = 10 g / 16 g/mol
Moles = 0.625 moles
Secondly calculate the moles of CO₂ produces theoretically,
According to equation,
1 mole of CH₄ produces = 1 mole of CO₂
So,
0.625 moles of CH₄ will produce = X moles of CO₂
Solving for X,
X = 1 mole × 0.625 moles / 1 mole
X = 0.625 moles of CO₂
At last calculate mass of CO₂ as,
Mass = Moles × M.Mass
Mass = 0.625 mole × 44 g/mol
Mass = 27.5 g ≈ 27 g
Conclusion:
From above calculation it can be concluded that this reaction is following law of conservation of mass. There is neither a gain nor a loss of mass during the reaction. Also, this can be made possible when the given amount of methane is provided with excess of O₂ gas so that the methane is completely combusted.
