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ch4aika [34]
2 years ago
13

Question 2 of 45

Chemistry
2 answers:
sweet [91]2 years ago
4 0

Answer:

6 I think lol hope this helps

Leya [2.2K]2 years ago
3 0

Carbon has 6 neutrons, 6 protons and 6 electrons.

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PLEASE HELP!
fgiga [73]
150/30 = 5
HF1 20/2 = 10
HF2 10/2 = 5
HF3 5/2 = 2.5
HF4 2.5/2 = 1.25
HF5 1.25/2 = 0.625
Answer: 0.63g
5 0
2 years ago
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The inputs for cellular respiration are
katrin [286]
Glycolysis--The breakdown of a glucose molecule into two three-carbon pieces called pyruvate. You will notice that very little ATP is produced in this step and no oxygen is required. ... This step is also where other molecules besides glucose may be fed into the cell respiration<span> process, especially lipids.</span>
5 0
3 years ago
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What is the molecular weight of magnesium chloride?​
valentinak56 [21]

Answer:

Magnesium chloride/Molar mass

95.211 g/mol

Explanation:

6 0
3 years ago
Electromagnetic radiation with a wavelength of 525 nm appears as green light to the human eye. The energy of one photon of this
Sedbober [7]

<u>Answer:</u> The energy of one photon of the given light is 3.79\times 10^{-19}J

<u>Explanation:</u>

To calculate the energy of one photon, we use Planck's equation, which is:

E=\frac{hc}{\lambda}

where,

\lambda = wavelength of light = 525nm=5.25\times 10^{-7}m        (Conversion factor:  1m=10^9nm  )

h = Planck's constant = 6.625\times 10^{-34}J.s

c = speed of light = 3\times 10^8m/s

Putting values in above equation, we get:

E=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{5.25\times 10^{-7}mm}\\\\E=3.79\times 10^{-19}J

Hence, the energy of one photon of the given light is 3.79\times 10^{-19}J

3 0
3 years ago
Really need help!
WARRIOR [948]
The magnitude of a star as it would appear to a hypothetical observer at a distance of 10 parsecs or 32.6 light-years. This rates how visible celestial bodies are when they are all viewed from the same distance. Luminosity: The brightness of a star in comparison with that of the sun.
7 0
3 years ago
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