Answer:
y > 4x - 2
Step-by-step explanation:
y-intercept is at -2
slope is rise by 4, run by 1
if you don't know where to shade, select a point and plug it in to see if T or F
example (0, 0)
is 0 > 4(0) - 2
is 0 > -2 True, so shade to the left because this is where (0,0) is
Answer:
10 2/3
Step-by-step explanation:
Multiply 4 and 2 and then multiply 2 and 4. If you do that then you get 8 8/3. You then just take the numerator and turn it into whole numbers to get 10 2/3.
The illegal values of b are when the denominator equals 0.
So,
gives you (b-4)(b+2)=0
Therefore, b=4 and b=-2, which is answer A.
That "9 minutes" doesn't affect the outcome!
How many pieces of candy are in the bag at the beginning? How many of those are "fruit tart chews?" Write a fraction involving these 2 counts. Remember that Britany immediately eats what she draws from the bag, so the 2nd time around, there are only 19 pieces, not 20. What is the prob. that she will pick a jelly treat on her second draw?
Because these experiments are independent, you can find the joint probability by multiplying the 2 probabilities together. Please show your work.
If you're just integrating a vector-valued function, you just integrate each component:


The first integral is trivial since
.
The second can be done by substituting
:

The third can be found by integrating by parts:


