When a skin diver is on the top of the water at 1.03 atm, her lung volume is 3.62L. How will the volume of her lungs change as s
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Answer:
Explanation:
Since we are given the mass, specific heat, and change in temperature, we should use this formula for heat:
The substance's mass is 450.0 grams, the specific heat is 1.264 J/g°C, and the change in temperature is 7.1 °C.
Substitute the values into the formula.
Multiply the first 2 values together. The grams will cancel out.
Multiply again. This time, the degrees Celsius cancel out.
<u>4038.48 Joules</u> of heat energy are released.
SF₆ in the air at a concentration of 1.0 ppb, exerts a partial pressure of 1.0 × 10⁻⁹ atm. At this concentration, 2.3 × 10¹⁰ molecules of SF₆ are contained in 1.0 cm³ of air at 46 °C.
First, we will calculate the partial pressure of SF₆ using the following expression.
where,
- pSF₆: partial pressure of SF₆
- P: total pressure of air (we will assume it is 1 atm)
- ppb: concentration of SF₆ in parts per billion
Then, we will convert 1.0 cm³ to L using the following conversion factors:
- 1 cm³ = 1 mL
- 1 L = 1000 mL
Next, we will convert 46 °C to Kelvin using the following expression.
Afterward, we calculate the moles (n) of sulfur hexafluoride using the ideal gas equation.
Finally, we will convert 3.8 × 10⁻¹⁴ mol to molecules using Avogadro's number.
SF₆ in the air at a concentration of 1.0 ppb, exerts a partial pressure of 1.0 × 10⁻⁹ atm. At this concentration, 2.3 × 10¹⁰ molecules of SF₆ are contained in 1.0 cm³ of air at 46 °C.
You can learn more about partial pressure here: brainly.com/question/13199169