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blsea [12.9K]
2 years ago
7

What is the purpose of the arrow in a chemical equation? A. It indicates the direction in which the reaction occurs. B. It separ

ates the elements from the compounds. C. It indicates the direction of increase in the number of molecules. D. It indicates the direction of heat movement in a reaction.

Chemistry
2 answers:
Andrej [43]2 years ago
7 0

A is most likely correct cause B and C make no sense, D is a maybe but A is right

solmaris [256]2 years ago
6 0

A is the answer to this question. Hope this helps!

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A(n) ____________________ is a compound that turns litmus blue and is often found in soaps and detergents.
ehidna [41]
B. base
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8 0
3 years ago
A 3.452 g sample containing an unknown amount of a Ce(IV) salt is dissolved in 250.0-mL of 1 M H2SO4. A 25.00 mL aliquot is anal
SOVA2 [1]

Answer:

1,812 wt%

Explanation:

The reactions for this titration are:

2Ce⁴⁺ + 3I⁻ → 2Ce³⁺ + I₃⁻

I₃⁻ + 2S₂O₃⁻ → 3I⁻ + S₄O₆²⁻

The moles in the end point of S₂O₃⁻ are:

0,01302L×0,03428M Na₂S₂O₃ = 4,463x10⁻⁴ moles of S₂O₃⁻. As 2 moles of S₂O₃⁻ react with 1 mole of I₃⁻, the moles of I₃⁻ are:

4,463x10⁻⁴ moles of S₂O₃⁻×\frac{1molI_{3}^-}{2molS_{2}O_{3}^-} = 2,2315x10⁻⁴ moles of I₃⁻

As 2 moles of Ce⁴⁺ produce 1 mole of I₃⁻, the moles of Ce⁴⁺ are:

2,2315x10⁻⁴ moles of I₃⁻×\frac{2molCe^{4+}}{1molI_{3}^-} = 4,463x10⁻⁴ moles of Ce(IV). These moles are:

4,463x10⁻⁴ moles of Ce(IV)×\frac{140,116g}{1mol} = <em>0,0625 g of Ce(IV)</em>

As the sample has a 3,452g, the weight percent is:

0,0625g of Ce(IV) / 3,452g × 100 = <em>1,812 wt%</em>

I hope it helps!

5 0
2 years ago
Provide two arguments on why you don't notice the land moving beneath you, defend your answer.​
AnnyKZ [126]

Answer:

The reference point is the ground.

Explanation:

•Moves slow that you don't notice hope this helps you :) god loves you :)

5 0
3 years ago
In the past mining companies were not made responsible for the clean-up of any of
aliya0001 [1]
D because it was abandoned
4 0
3 years ago
Does potassium nitrate (KN03) incorporate ionic bonding, covalent bonding, or both? Explain.
ladessa [460]

Answer: KNO_3 incorporates both ionic bonding and covalent bonding.

Explanation:

A covalent bond is formed when an element shares its valence electron with another element. This bond is formed between two non metals.

An ionic bond is formed when an element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element and the element which accepts the electrons is known as electronegative element. This bond is formed between a metal and an non-metal.

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

Here potassium is having an oxidation state of +1 called as K^{+} cation and nitrate NO_3^{-} is an anion with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral KNO_3. NO_3^- is formed by sharing of electrons between two non metals nitrogen and oxygen.

Thus KNO_3 incorporates both ionic bonding and covalent bonding.

4 0
3 years ago
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