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blsea [12.9K]
3 years ago
7

What is the purpose of the arrow in a chemical equation? A. It indicates the direction in which the reaction occurs. B. It separ

ates the elements from the compounds. C. It indicates the direction of increase in the number of molecules. D. It indicates the direction of heat movement in a reaction.

Chemistry
2 answers:
Andrej [43]3 years ago
7 0

A is most likely correct cause B and C make no sense, D is a maybe but A is right

solmaris [256]3 years ago
6 0

A is the answer to this question. Hope this helps!

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Relative to protons, electrons have:
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Answer:

<u><em>(B.) a significantly lower mass that protons</em></u>

Explanation:

The mass (in g) of an electron is 9.11 ×10^{-28}g, which is significantly lower than the mass of protons and neutrons which are approximately the same. They are extremely small (equal to 0 amu), contributing nothing to the overall mass of the atom.

The nucleus has a mass of 1 amu and is positively charged.

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3 years ago
Complete the passage: During the process of polymerization, combine by sharing electrons. This process forms a , which is made o
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During the process of polymerization, monomers combine by sharing electrons. This process forms a polymer, which is made of repeating subunits. The resulting material is used in a variety of ways.


Hope this helps!


~CoCo

9 0
3 years ago
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Which of the following statements is true? Radiation is the transfer of heat between objects which are not touching. An insulato
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Answer:

Radiation is the transfer of heat between objects which are not touching. I think

Explanation:

3 0
1 year ago
The activation energy of an uncatalyzed reaction is 95kJ/mol. The addition of a catalyst lowers the activation energy to 55kJ/mo
notka56 [123]

Answer:

a) at 25°C the rate of reaction increases by a factor of 1,027*10^7

b) at 25°C the rate of reaction increases by a factor of 1,777*10^5

Explanation:

using the Arrhenius equation

k= ko*e^(-Ea/RT)

where

k= reaction rate

ko= collision factor

Ea= activation energy

R= ideal gas constant= 8.314 J/mol*K

T= absolute temperature

for the uncatalysed reaction

k1= ko*e^(-Ea1/RT)

for the catalysed reaction

k2= ko*e^(-Ea2/RT)

dividing both equations

k2/k1= e^(-(Ea2-Ea1)/RT)

a) at 25°C

k2/k1 = e^(-(55kJ/mol-95kJ/mol)/(8.314J/mol*K*298K)* (1000J/kJ ) ) = 1,027*10^7

therefore at 25°C , k2/k1 = 1,027*10^6

b) at 125°C

k2/k1 = e^(-(55kJ/mol-95kJ/mol)/(8.314J/mol*K*298K)* (1000J/kJ ) ) = 1,777*10^5

therefore at 125°C , k2/k1 = 1,777*10^5

Note:

when the catalysts is incorporated, the catalysed reaction and the uncatalysed one run in parallel and therefore the real reaction rate is

k real = k1 + k2 = k2 (1+k1/k2)

since k2>>k1 → 1+k1/k2 ≈ 1 and thus k real ≈ k2

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3 years ago
You are trying to determine the volume of the balloon needed to match the density of the air in the lab. You know that if you ca
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To solve this problem, we must be given first the density of air at 20 degrees Celsius. Looking up online, this is equal to:

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so that the volume is:

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