The number of shells increase, the energy level their outer shell have decreases as we go down wards,
Answer:
it opposes motion. the object would continue to slide forever if not stopped by another object.
Answer:
C
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Answer:
The concentration of [A⁻] is 0,0166M
Explanation:
In the equilibrium of a weak acid:
HA ⇄ A⁻ + H⁺
The solution of a weak acid contains, initially, the concentration of HA is Y. In equilibrium, the concentrations of each compound are:
[HA] = Y-x
[A⁻] = x
[H⁺] = x
That means [H⁺] = [A⁻].
The pH is defined as -log₁₀ [H⁺]. As the pH was 1,78:
1,78 = -log₁₀ [H⁺]
0,0166M = [H⁺]
As [H⁺] = [A⁻], <em>the concentration of [A⁻] is 0,0166M</em>
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I hope it helps!
Answer:
C
Explanation:
When the Kb is given, the Henderson-Hasselbalch equation can be used to calculate the pOH of a buffer solution:
pOH = pKb + log ([A⁻] / [HA]) = -log(Kb) + log ([BH+] / [B])
Here, moles can be used in place of the concentration since the pairs listed are both dissolved in 5L, which cancel due to the fraction in the logarithm.
a) pOH = -log(1.8 x 10⁻⁵) + log(1.5/1.0) = 4.92
pH = 14 - pOH = 14 - 4.92 = 9.08
b) pOH = -log(1.8 x 10⁻⁵) + log(1.0/1.5) = 4.57
pH = 14 - pOH = 14 - 4.57 = 9.43
c) pOH = -log(1.7 x 10⁻⁹) + log(1.5/1.0) = 8.95
pH = 14 - pOH = 14 - 8.95 = 5.05
d) pOH = -log(1.7 x 10⁻⁹) + log(1.0/1.5) = 8.59
pH = 14 - pOH = 14 - = 5.41
