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monitta
3 years ago
12

What is 11/6 + 11/6 in fractions

Chemistry
2 answers:
Andreyy893 years ago
6 0
3 2/3 is your answer
Kryger [21]3 years ago
5 0
Since the denominator, you can just add 11+11
11+11=22
22/6 can also mean 3 4/6 or further simply as 3 2/3
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If 1.00 g of reactant a is mixed with 2.00 g of reactant b, what is the theoretical yield of product d, in grams (g)? the molar
WARRIOR [948]

The chemical reaction is as follows:

a+b\rightarrow d

Mass of reactant a is 1 g and molar mass is 94 g/mol. Converting mass into number of moles as follows:

n=\frac{m}{M}=\frac{1g}{94 g/mol}=0.0106 mol

Now, 1 mole of reactant a gives 1 mole of product d thus, 0.0106 mol of reactant a gives 0.0106 mol of product d.

Molar mass of product d is 125 g/mol, converting number of moles into mass as follows:

m=n×M=0.0106 mol×125 g/mol=1.33 g

Similarly, molar mass of reactant b is 118 g/mol and mass is 2 g, converting mass into number of moles,

n=\frac{m}{M}=\frac{2g}{118 g/mol}=0.017 mol

1 mol of reactant b gives 1 mol of product d thus, 0.017 mol will give 0.017 mol of product d.

Converting number of moles into mass as follows:

m=n×M=0.017 mol×125 g/mol=2.12 g

Here, reactant that produces lesser product is limiting reactant and the amount of product it forms is theoretical yield.

Therefore, theoretical yield is 1.33 g.


6 0
3 years ago
Liquid octane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 97. g of octane is mi
zhannawk [14.2K]

Answer: 61 grams

Explanation:

To calculate the number of moles, we use the equation:

\text{Number of moles of octane}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{97g}{114g/mol}=0.85moles

\text{Number of moles of oxygen}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{150g}{32g/mol}=4.69moles

The chemical equation for the combustion of octane in oxygen follows the equation:

2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O

By stoichiometry of the reaction;

25 moles of oxygen react with 2 moles of octane

4.69 moles of oxygen react with=\frac{2}{25}\times 4.69=0.37  moles of octane

Thus, oxygen is the limiting reagent as it limits the formation of product and octane is the excess reagent.

25 moles of oxygen produce 18 moles of water

4.69 moles of oxygen produce=\frac{18}{25}\times 4.69=3.38  moles of water.

Mass of water produced=moles\times {\text{Molar mass}}=3.38\times 18g/mol=61g

The maximum mass of water that could be produced by the chemical reaction is 61 grams.

6 0
3 years ago
HELP!!!!! How much does a sample of Argon weigh if it occupies 25.4 L at a pressure of 2.45 atm and a temperature of 482 K?
Artist 52 [7]

Answer:

62.82 g

Explanation:

From the question,

PV = nRT.................. Equation 1

Where P = Pressure, V = Volume, n = number of moles of argon, R = molar gas constant, T = Temperature.

But,

Number of mole (n) = mass (m)/molar mass(m')

n = m/m'................... Equation 2

Substitute equation 2 into equation 1

PV = (m/m')RT.............. Equation 3

From the question, we were asked to find m.

There make m the subject of formula in equation 3

m = PVm'/RT.............. Equation 4

Given: P = 2.45 atm, V = 25.4 L, T = 482 K

Constant: R = 0.082 atm.dm³.K⁻¹.mol⁻¹, m' = 39.9 g/mol

Substitute these values into equation 4

m = (2.45×25.4×39.9)/(0.082×482)

m = 62.82 g.

5 0
3 years ago
Which quantity does a light-year measure?<br><br> A) distance<br> B) speed<br> C) time<br> D) volume
tatuchka [14]

Answer:

speed

Explanation:

6 0
3 years ago
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scoray [572]
Thermometer
Probably a digital thermocouple with high resolution
7 0
3 years ago
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