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monitta
3 years ago
12

What is 11/6 + 11/6 in fractions

Chemistry
2 answers:
Andreyy893 years ago
6 0
3 2/3 is your answer
Kryger [21]3 years ago
5 0
Since the denominator, you can just add 11+11
11+11=22
22/6 can also mean 3 4/6 or further simply as 3 2/3
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What is the mole to mole ration between oxygen gas and water
Karolina [17]

<u>Answer:</u>

<em>The mole to mole ratio between oxygen gas and water is 2 : 1</em>

<em></em>

<u>Explanation:</u>

Balancing is making the number of atoms of each element same on both the sides  (reactant and product side).

To find the number of atoms of each element we multiply coefficient and the subscript  

For example  

5 Ca_1 Cl_2 contains  

5 × 1 = 5 ,Ca atoms and

5 × 2 = 10, Cl atoms  

If there is a bracket in the chemical formula  

For example  

3Ca_3 (P_1 O_4 )_2

we multiply coefficient × subscript × number outside the bracket to find the number of atoms  

(Please note: 3 is the coefficient, and if there is no number given then 1 will be the coefficient )

So

3 × 3 = 9 , Ca atoms  

3 × 1 × 2 = 6, P atoms  

3 × 4 × 2 = 24, O atoms are present.

So

The balanced chemical equation is

2H_2 O >2H_2+1O_2

The number which stands in front of the chemical formula is the coefficient and it represents the number of moles of each substance.

So we see here 2 is the coefficient of H_2 O and 1 is the coefficient of O_2  

So the mole ratio of water and oxygen gas is 2 : 1

(Answer)

8 0
3 years ago
The loss of static energy electric charges move off an object is called
shutvik [7]
It is called electric discharge. Electric discharge can occur slowly.
6 0
3 years ago
Read 2 more answers
Aspartame, phenylalanine, and aspartic acid were examined by thin‑layer chromatography (TLC) using ninhydrin as the visualizatio
Marizza181 [45]

Answer:

Explanation:

The following precautions should be followed for a safe and efficient laboratory environment:

The TLC plate should be laid on a paper towel, to ease picking it from the bench top.

The used TLC spotters and the used TLC plates in the appropriate waste containers provided for this purpose should be placed in the blood.

Spills should be cleaned up and contaminated surfaces should be washed with water.

The pipette and/or glassware should be rinsed again with the distilled water, in case there is the slightest doubt about the contamination.

Everything used should be washed with distilled water, including the pipettes.

4 0
3 years ago
Identify the oxidizing agent and the reducing agent in the following reactions: (i) 8NH3( g) + 6NO2( g) =&gt; 7N2( g) + 12H2O( l
shusha [124]

Answer:

(i)  Oxidizing Agent: NO2 / Reducing Agent NH3-

(ii) Oxidizing Agent AgNO3 / Reducing Agent Zn

Explanation:

(i) 8NH3( g) + 6NO2( g) => 7N2( g) + 12H2O( l)

In this reaction, both two reactants contain nitrogen with a different oxidation number and produce only one product which contains nitrogen with a unique oxidation state. So, nitrogen is oxidized and reduced in the same reaction.

Nitrogen Undergoes a change in oxidation state from 4+ in NO2 to 0 in N2. It is reduced because it gains electrons (decrease its oxidation state). NO2 is the oxidizing agent (electron acceptor).

Nitrogen Changes from an oxidation state of 3- in NH3 to 0 in N2. It is oxidized because it loses electrons (increase its oxidation state). NH3 is the reducing agent (electron donor)

(ii) Zn(s) +AgNO3(aq) => Zn(NO3)2(aq) + Ag(s)

Ag changes oxidation state from 1+ to 0 in Ag(s).

Ag is reduced because it gains electrons and for this reason and AgNO3 is the oxidizing agent (electron acceptor)

Zn Changes from an oxidation state of 0 in Zn(s) to 2+ in Zn(NO3)2. It is oxidized and for this reason Zn is the reducing agent (electron donor).

Balanced equation:

Zn(s) +2AgNO3(aq) => Zn(NO3)2(aq) + 2Ag(s)

 

4 0
3 years ago
an ideal gas is at a pressure 1.00 x 10^5 N/m^2 and occupies a volume 11.00 m^3. If the gass is compressed to a volume of 1.00 m
bogdanovich [222]

Answer:

P_2=1.1x10^6Pa

Explanation:

Hello.

In this case, we can solve this problem by applying the Boyle's law which allows us to understand the pressure-volume behavior as a directly proportional relationship:

P_1V_1=P_2V_2

In such away, knowing the both the initial pressure and volume and the final volume, we can compute the final pressure as shown below:

P_2=\frac{P_1V_1}{V_2}

Consider that the given initial pressure is also equal to Pa:

P_2=\frac{1.00x10^5Pa*11.00m^3}{1.00m^3}\\ \\P_2=1.1x10^6Pa

Which stands for a pressure increase when volume decreases.

Regards.

4 0
3 years ago
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