A solution (in this experiment solution of NaNO₃) freezes at a lower temperature than does the pure solvent (deionized water). The higher the
solute concentration (sodium nitrate), freezing point depression of the solution will be greater.
Equation describing the change in freezing point:
ΔT = Kf · b · i.
ΔT - temperature change from pure solvent to solution.
Kf - the molal freezing point depression constant.
b - molality (moles of solute per kilogram of solvent).
i - Van’t Hoff Factor.
First measure freezing point of pure solvent (deionized water). Than make solutions of NaNO₃ with different molality and measure separately their freezing points. Use equation to calculate Kf.
Answer:
yes
Explanation:
because I think it is correct fo u
0.88qt
Explanation:
Given parameters:
Density of ebony wood = 1.174g/ml
Mass of wood = 2.1549lb
Unknown:
Volume of the wood in quarts = ?
Solution:
Density is defined as the mass per unit volume of a substance.
Mass is the quantity of matter the wood contains.
Volume is the space it occupies.
To solve this problem, convert the mass form pounds into grams and plug into the density equation to find volume.
Then convert the volume from mL to quarts.
Density = 
Volume = 
1 pound = 453.592g
2.1549 lb = 2.1549 x 453.592 = 977.5g
Volume =
= 832.6mL
1 quart = 946.353mL
Therefore 832.6mL x
= 0.88qt
learn more:
Density brainly.com/question/8441651
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B - two hydrogen atoms and one oxygen atom
Answer:
Explanation:
Option A is the correct answer