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3 years ago

A family is purchasing concrete in order to create a foundation for a rectangular outdoor

Mathematics

1 answer:

Murrr4er [49]3 years ago

4 0

Answer:

42.5 Cubic Yards

Step-by-step explanation:

To find volume of a rectangle you do length*width*height to get the volume, so 17*15*0.5(because 6 inches is half of a foot) you get 127.5, but they're asking for it in yards not feet so you need to divide 127.5 by 3 and that will give you 42.5.

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ASAP 26 POINTS

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23 is your answer. IT's 22.8 but rounded up its 23

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Which situations can be represented by a linear function?

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A linear function is when a variable y varies directly with a variable x. That is, when y increases, x also increases and the opposite is also true. THerefore, the correct answer from the choices listed above is the first option. Every day, the number of bacteria in the dish is 3 times what it was the previous day can be <span>represented by a linear function.</span>

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A football player punts a ball. The path of the ball can be modeled by the equation y = –0.004x2 + x + 2.5, where x is the horiz

Galina-37 [17]

The answer is <span>252.5 ft

</span><span>y = –0.004x</span>²<span> + x + 2.5
Let's take y = 0 and we'll get the quadratic equation:

</span>–0.004x² + x + 2.5 = 0
The general formula for quadratic equation is:
ax² + bx + c = 0

a = -0.004
b = 1
c = 2.5

$x_{1,2} = \frac{-b+/- \sqrt{ b^{2}-4ac} }{2a} =\frac{-1+/- \sqrt{ 1^{2}-4*(-0.004)*2.5} }{2*(-0.004)} = \frac{-1+/- \sqrt{1+0.04} }{-0.008} = \\ 
=\frac{-1+/- \sqrt{1.04} }{-0.008} = \frac{-1+/-1.02}{-0.008}$

$x_1=\frac{-1+1.02}{-0.008} = \frac{0.02}{-0.008} = -2.5 \\ 
x_2=\frac{-1-1.02}{-0.008} = \frac{2.02}{-0.008} = 252.5$

Since distance cannot be negative (x1), the correct answer is x2 = 252.5 ft

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What times what equals 234

inessss [21]

2 x 117
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6 x 39
9 x 26
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3 years ago

A manager is comparing wait times for customers in a coffee shop based on which employee is

anyanavicka [17]

Using the t-distribution, as we have the standard deviation for the sample, it is found that there is a significant difference between the wait times for the two populations.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, we test if there is no difference, that is:

$H_0: \mu_A - \mu_B = 0$

At the alternative hypothesis, it is tested if there is difference, that is:

$H_1: \mu_A - \mu_B = 0$

<h3>What are the mean and the standard error of the distribution of differences?</h3>

For each sample, we have that:

$\mu_A = 73, s_A = \frac{2}{\sqrt{100}} = 0.2$

$\mu_B = 74, s_B = \frac{4}{\sqrt{100}} = 0.4$

For the distribution of differences, we have that:

$\overline{x} = \mu_A - \mu_B = 73 - 74 = -1$

$s = \sqrt{s_A^2 + s_B^2} = \sqrt{0.2^2 + 0.4^2} = 0.447$

<h3>What is the test statistic?</h3>

It is given by:

$t = \frac{\overline{x} - \mu}{s}$

In which $\mu = 0$ is the value tested at the null hypothesis.

Hence:

$t = \frac{\overline{x} - \mu}{s}$

$t = \frac{-1 - 0}{0.447}$

$t = -2.24$

<h3>What is the p-value and the decision?</h3>

Considering a one-tailed test, as stated in the exercise, with 100 - 1 = 99 df, using a t-distribution calculator, the p-value is of 0.014.

Since the p-value is less than the significance level of 0.05, it is found that there is a significant difference between the wait times for the two populations.

More can be learned about the t-distribution at brainly.com/question/16313918

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