All categories

4 years ago

Explain the differences in the solubilities of the gases in the table by completing the following sentences.

1 answer:

7 0

1. Compared to oxygen, nitrogen's __________ makes it more difficult for water molecules to the surround nitrogen molecules.
2. The high solubility of sulfur dioxide can be explained by its ____________. 
3. Nitric oxide is more soluble than nitrogen and oxygen because of its _______________. 
4. Compared to nitrogen, the ___________ of ethylene makes it more soluble in water. 

CHOICES are: 
a. shorter bond length 
b. ability to react with water 
c. larger molecular size 
d. polarity

answers: a, b, d, c.

You might be interested in

Which statement best describes the lattice structure of solid sodium chloride?

zlopas [31]

It is A , each sodium ion is surrounded by one chloride ion . the explanation is because Chlorine needs one more electron to have a full outer most shell , and sodium has one electron in its outer most shell .

7 0

3 years ago

Why do organisms created from sexual reproduction show a greater variation?

Tomtit [17]

The answer is A. How this helps

6 0

3 years ago

PLEASE HELP!!

jeka57 [31]

I think it is C. i took a quiz on that.

3 0

3 years ago

Find all the square roots 225

KiRa [710]

Answer: 15

The square root of 225 is 15.

Explanation:

https://api-project-1022638073839.appspot.com/questions/how-do-you-find-the-square-root-of-1849#642333

5 0

3 years ago

A quantity of 0.0250 mol of a gas initially at 0.050 L and 19.0°C undergoes a constant-temperature expansion against a constant

KiRa [710]

Answer:

$V_2=2.995L\\\\W=248.5J$

Explanation:

Hello,

In this case, for us to compute the final volume we apply the Boyle's law that analyzes the pressure-volume temperature as an inversely proportional relationship:

$P_1V_1=P_2V_2$

So we solve for $V_2$ by firstly computing the initial pressure:

$P_1=\frac{nRT}{V_1}=\frac{0.025mol*0.082\frac{atm*L}{mol*K}*(19+273.15)K}{0.050L} =11.98atm$

$V_2=\frac{P_1V_1}{P_2}=\frac{11.98atm*0.050L}{0.200atm}\\ \\V_2=2.995L$

Finally, we can compute the work by using the following formula:

$W=nRTln(\frac{V_2}{V_1} )=0.025mol*8.314\frac{J}{mol*K}*(19.0+273.15)K*ln(\frac{2.995L}{0.050L}) \\\\W=248.5J$

Best regards.

4 0

3 years ago