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aivan3 [116]
3 years ago
6

Electron configuration for Ar

Chemistry
1 answer:
timurjin [86]3 years ago
5 0

Answer : The electronic configuration of argon (Ar) is, 1s^22s^22p^63s^23p^6

Explanation :

Element is, Argon (Ar)

Atomic number of argon = 18

The number of electrons = 18

As we know that the number of electrons is equal to the number of protons and the number of proton is equal to the atomic number.

Electronic configuration : It is defined as the arrangement or distribution of electron of atom in a atomic orbital.

Hence, the electronic configuration of argon is,

1s^22s^22p^63s^23p^6

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Answer:

M_{per}= 52.86

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Explanation:

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40 wt% methanol - 60 wt% water 200 kg

m_{met1}=200 kg * 0.4= 80 kg

m_{wat1}=200 kg * 0.6= 120 kg

<u>Second mixture</u>:

70 wt% methanol - 30 wt% water 150 kg

m_{met2}=150 kg * 0.7= 105 kg

m_{wat2}=150 kg * 0.3= 45 kg

Final mixture:

m_{metF=80 kg + 105 kg= 185 kg

m_{watF}=120 kg + 45 = 165 kg

M_{per}=\frac{185 kg}{185 kg + 165 kg}*100= 52.86

W_{per}=\frac{165 kg}{185 kg + 165 kg}*100=47.14

If, the compositions are constant, the only variables are the mass of each mixture used in the final one, so there can be only one independent balance.

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A piece of metal has a volume of 30.0cm3 and a mass of 252g. What is its density? what metal do you think this is?
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Answer:

                    1.8 moles of O₂

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So,

                1.8 moles of O₂ will be produced by  =  X moles of O₂

Solving for X,

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Stoichiometric problems in which moles are given and moles or other reactant or product asked are the simplest problems. One should only write the balanced chemical equation and perform above method to find the required moles.

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Answer:

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