To answer this, you will use the area of 900 square yards to determine the distances between the bases. Each side of the square is 30 yards, so it will be 30 yards from 1st to home and from 1st to 2nd.
The distance from home to 2nd is a diagonal in the square (the hypotenuse).
You will use the Pythagorean Theorem to find this distance.
a^2 + b^2 = c^2
30^2 + 30 ^2 = c^2
900 + 900 + c^2
1800 = c^2
The square root of 1800 is approximately 42.4 yards.
The ball travels approximately 42.4 yards.
Answer
Step-by-step explanation:
Let x be the fasteners
95% of x passed, and 5% of x failed
20% of the 5% which failed are defective, remaining the 80% of the failed 5%.
Now 40% of this 80% of the 5% which failed are scrapped, meaning only the remaining 60% passed second inspection.
Thus
a). The proportion ;
60% of 80% of 5% of x
mathematically
= 60/100 × 80/100 × 5/100
= 0.024 or 2.4%
b) initially 95% passed and later on 2.4% pass again. Therefore total that passed = 95%+2.4%=97.4%
c) probability that it passed on first inspection is 95/100
Percentage that went through recrimping = 80% of 5% = 80/100 × 5/100 = 1/25 or 0.04 or 4%
Thus probability of passing and not going through recrimping
= 1 - (1/25) = 0.96 or 96%
(-9k+8k)*-1
9k-8k=1k
1k*-1=-1k
your answer is -1k
Answer:
5a. -0.4 m/s²
5b. 290 m
6. 12.9 s
7. 100 s
8. 17.2 km/hr
Step-by-step explanation:
5. "While approaching a police officer parked in the median, you accelerate uniformly from 31 m/s to 27 m/s in a time of 10 s.
a. What is your acceleration?
b. How far do you travel in that time?"
Given:
v₀ = 31 m/s
v = 27 m/s
t = 10 s
Find: a and Δx
v = at + v₀
(27 m/s) = a (10 s) + (31 m/s)
a = -0.4 m/s²
Δx = ½ (v + v₀) t
Δx = ½ (27 m/s + 31 m/s) (10 s)
Δx = 290 m
6. "If a pronghorn antelope accelerates from rest in a straight line with a constant acceleration of 1.7 m/s², how long does it take for the antelope to reach a speed of 22 m/s?"
Given:
v₀ = 0 m/s
v = 22 m/s
a = 1.7 m/s²
Find: t
v = at + v₀
(22 m/s) = (1.7 m/s²) t + (0 m/s)
t = 12.9 s
7. "A 1200 kg airplane starts from rest and moves forward with a constant acceleration of 5 m/s² along a runway that is 250 m long. How long does it take the plane to travel the 250 m?"
Given:
v₀ = 0 m/s
a = 5 m/s²
Δx = 250 m
Find: t
Δx = v₀ t + ½ at²
(250 m) = (0 m/s) t + ½ (5 m/s²) t²
t = 100 s
8. "During a marathon, a runner runs the first 10 km in 0.58 hours, the next 10 km in 0.54 hours and the last 10 km in 0.62 hours. What is the average speed of the runner during that marathon?"
This isn't a constant acceleration problem, so there's no need for a chart.
Average speed = total distance / total time
v = (10 km + 10 km + 10 km) / (0.58 hr + 0.54 hr + 0.62 hr)
v = 30 km / 1.74 hr
v = 17.2 km/hr
Answer:
x - 6.
Step-by-step explanation:
3(x-6) = 3x -18
3x -18 + 4x + 12 -6x = x - 6
