Answer:
great
Explanation:
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Answer:
<h2>120°C</h2>
Explanation:
Step one:
given data
T_{wi} = 20^{\circ}C
T_{Ai}=1000K
T_{Ae}= 400kPa
P_{Wi}=200kPa
P_{Ai}=125kPa
P_{We}=200kPa
P_{Ae}=100kPa
m_A=2kg/s
m_W=0.5kg/s
We know that the energy equation is
making the subject of formula we have
from the saturated water table B.1.1 , corresponding to
from the ideal gas properties of air table B.7.1 , corresponding to T=1000K
the enthalpy is:
from the ideal gas properties of air table B.7.1 corresponding to T=400K
Step two:
substituting into the equation we have
from saturated water table B.1.2 at we can obtain the specific enthalpy:
we can see that , hence there are two phases
from saturated water table B.1.2 at
Answer:
3.99 mm
Explanation:
To treat a diffusive process in function of time and distance we need to solve 2nd Ficks Law. This a partial differential equation, with certain condition the solution looks like this:
Where Cs is the concentration in the surface of the solid
Cx is the concentration at certain deep X
Co is the initial concentration of solute in the solid
and erf is the error function
First we need to solve the Cs-Cx/Cs-Co on the left to search the corresponding value later on a table.
We look on a table and we see for erf(z)=0.4284 z=0.40
Then we solve for x
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Answer:
Explanation:
The steam turbine is modelled after the First Principle of Thermodynamics. Changes in potential and kinetic energy are negligible:
The heat rate is:
From steam and saturated tables, specific enthalpies at inlet and outlet are found:
Inlet - Superheated vapor
Outlet - Saturated vapor
The loss rate is: