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larisa86 [58]
2 years ago
11

. A normal-weight concrete has an average compressive strength of 20 MPa. What is the estimated flexure strength

Engineering
1 answer:
bulgar [2K]2 years ago
4 0

Answer:

2.77mpa

Explanation:

compressive strength = 20 MPa. We are to find the estimated flexure strength

We calculate the estimated flexural strength R as

R = 0.62√fc

Where fc is the compressive strength and it is in Mpa

When we substitute 20 for gc

Flexure strength is

0.62x√20

= 0.62x4.472

= 2.77Mpa

The estimated flexure strength is therefore 2.77Mpa

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A_____ transducer is a device that can convert an electronic controller output signal into a standard pneumatic output. A. pneum
makkiz [27]

Answer:

The correct answer is

option C. current to pneumatic (V/P)

Explanation:

A current to pneumatic controller is  basically used to receive an electronic signal from a controller and converts it further into a standard pneumatic output signal which is further used to operate a positioner or control valve. These devices are reliable, robust and accurate.

Though Voltage and current to pressure transducers are collectively called as electro pneumatic tranducers and the only electronic feature to control output pressure in them is the coil.

6 0
3 years ago
.The war of the currents in the 1880's involved Thomas Edison and Nikola Tesla on a reality TV show stranded on an island. Each
natali 33 [55]

Answer:

True

Explanation:

Nikola Tesla defeated Thomas Edison in the AC/DC battle of electric current.

7 0
3 years ago
technician A says that voltage is electric pressure .Technician B says the amperage is electrical flow who is right
Dmitrij [34]

Answer:

I would say technician A

Explanation:

Definition of voltage- An electromotive force or potential difference expressed in volts.

electromotive force is pressure so technician A would make sense.

5 0
3 years ago
How many points do you need to define for the rectangle
Rudik [331]

Answer:

Two points

Explanation:

3 0
3 years ago
zener shunt regulator employs a 9.1-V zener diode for which VZ = 9.1 V at IZ = 9 mA, with rz = 40 and IZK= 0.5 mA. The available
gulaghasi [49]

Answer:

V_z=9.1v

V_{zo}=8.74V

I=10mA

R=589 ohms

Explanation:

From the question we are told that:

Zener diode Voltage V_z=9.1-V

Zener diode Current I_z=9 .A

Note

rz = 40\\\\IZK= 0.5 mA

Supply Voltage V_s=15

Reduction Percentage P_r= 50 \%

Generally the equation for Kirchhoff's Voltage Law is mathematically given by

V_z=V_{zo}+I_zr_z

9.1=V_{z0}+9*10^{-3}(40)

V_{zo}=8.74V

Therefore

At I_z-10mA

V_z=V_{z0}+I_zr_z

V_z=8.74+(10*10^{-3}) (40)

V_z=9.1v

Generally the equation for Kirchhoff's Current Law is mathematically given by

-I+I_z+I_l=0

I=10mA+\frac{V_z}{R_l}

I=10mA+\frac{9.1}{0}

I=10mA

Therefore

R=\frac{15V-V_z}{I}

R=\frac{15-9.1}{10*10^{-3}}

R=589 ohms

5 0
3 years ago
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