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statuscvo [17]
2 years ago
13

Help thank you <3 :DDD

Engineering
1 answer:
Vika [28.1K]2 years ago
4 0

Answer:

Explanation:

its B

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A motor car shaft consists of a steel tube 30 mm internal diameter and 4 mm thick. The engine develops 10 kW at 2000 r.p.m. Find
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The maximum shear stress in the tube when the power is transmitted through a 4: 1 gearing is 28.98 MPa.

<h3>What is power?</h3>

Power is the energy transferred per unit time.

Torque is find out by

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10000 = 2π x 2000 x T / 60

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The gear ratio Ne / Ns =4/1

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Ts =Ps x 60/(2π x 500)

Ts =190.96 N.m

Maximum shear stress τ = 16/π x (T / (d₀⁴ - d₁⁴))

τ max =T/J x D/2
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Substitute the values into the equation, we get

τ max = 16 x 190.96 x 0.038 /π x (0.038⁴ - 0.03⁴)

τ max = 28.98 MPa.

Thus, the maximum shear stress in the tube is 28.98 MPa.

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generally compound curves are not filtered recommended for A. Road B. water way C. underground road D. rail way​
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