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statuscvo [17]
3 years ago
13

Help thank you <3 :DDD

Engineering
1 answer:
Vika [28.1K]3 years ago
4 0

Answer:

Explanation:

its B

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A venturi meter is to be installed in a 63 mm bore section of a piping system to measure the flow rate of water in it. From spac
Alex Ar [27]

Answer:

Throat diameter d_2=28.60 mm

Explanation:

 Bore diameter d_1=63mm  ⇒A_1=3.09\times 10^{-3} m^2

Manometric deflection x=235 mm

Flow rate Q=240 Lt/min⇒ Q=.004\frac{m^3}{s}

Coefficient of discharge C_d=0.8

We know that discharge through venturi meter

 Q=C_d\dfrac{A_1A_2\sqrt{2gh}}{\sqrt{A_1^2-A_2^2}}

h=x(\dfrac{S_m}{S_w}-1)

S_m=13.6 for Hg and S_w=1 for water.

h=0.235(\dfrac{13.6}{1}-1)

h=2.961 m

Now by putting the all value in

Q=C_d\dfrac{A_1A_2\sqrt{2gh}}{\sqrt{A_1^2-A_2^2}}

0.004=0.8\times \dfrac{3.09\times 10^{-3} A_2\sqrt{2\times 9.81\times 2.961}}{\sqrt{(3.09\times 10^{-3})^2-A_2^2}}

A_2=6.42\times 10^{-4} m^2

 ⇒d_2=28.60 mm

So throat diameter d_2=28.60 mm

     

4 0
3 years ago
\o you sell them?” "Fivepence farthing for one—Twopence for two,” the Sheep replied. "Then two are cheaper than one?” Alice said
NemiM [27]

Answer:

unusual and strange

Explanation:

3 0
3 years ago
HELP FAST WILL MARK BRAINLIEST (for a real answer)
Nata [24]

Answer:

B. 180 million joules

Explanation:

Apply the formula for heat transfer given as;

Q=m*c*Δt  where

Q = electrical energy consumed by the heater in joules

m= mass of air in the chamber in kg

c= specific heat of air in joules per kg degrees Celsius

Δt= change in temperatures in degrees Celsius

Given in the question;

m= 1200 kg

c= 1000 J/°C /kg

Δt = 180°-30°= 150° C

Substitute values in the equation to get Q as;

Q=m*c*Δt

Q= 1200 * 1000* 150

Q= 180000000 joules

Q = 180 million joules

<u>The correct answer option is B : 180 million joules.</u>

7 0
3 years ago
HW6P2 (20 points) The recorded daily temperature (°F) in New York City and in Denver, Colorado during the month of January 2014
Maurinko [17]

Answer & Explanation:

function Temprature

NYC=[33 33 18 29 40 55 19 22 32 37 58 54 51 52 45 41 45 39 36 45 33 18 19 19 28 34 44 21 23 30 39];

DEN=[39 48 61 39 14 37 43 38 46 39 55 46 46 39 54 45 52 52 62 45 62 40 25 57 60 57 20 32 50 48 28];

%AVERAGE CALCULATION AND ROUND TO NEAREST INT

avgNYC=round(mean(NYC));

avgDEN=round(mean(DEN));

fprintf('\nThe average temperature for the month of January in New York city is %g (F)',avgNYC);

fprintf('\nThe average temperature for the month of January in Denvar is %g (F)',avgDEN);

%part B

count=1;

NNYC=0;

NDEN=0;

while count<=length(NYC)

   if NYC(count)>avgNYC

       NNYC=NNYC+1;

   end

   if DEN(count)>avgDEN

        NDEN=NDEN+1;

   end

   count=count+1;

end

fprintf('\nDuring %g days, the temprature in New York city was above the average',NNYC);

fprintf('\nDuring %g days, the temprature in Denvar was above the average',NDEN);

%part C

count=1;

highDen=0;

while count<=length(NYC)

   if NYC(count)>DEN(count)

       highDen=highDen+1;

   end

   count=count+1;

end

fprintf('\nDuring %g days, the temprature in Denver was higher than the temprature in New York city.\n',highDen);

end

%output

check the attachment for additional Information

8 0
4 years ago
The average on a history exam (scored out of 100 points) was 85, with a standard deviation of 15. Is the distribution of the sco
Leviafan [203]

From the statement it is determined that the maximum limit is 100 and the lower limit is 0. At the same time there is an average of 85 that is closer to the upper limit than the lower limit, therefore the distribution will tend to occur to the left .

This will mean that people will begin to surround the average of 85 and that those who are 60, will be more than those who are below 50, and these 50 will be more than those who are by 40 and so on.

3 0
4 years ago
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