Temperature measures the average kinetic energy per molecule. True or False

umka21 [38]

Answer:

Approximately $3.01\; \rm m$ .

Explanation:

Decompose each vector into the sum of two vectors: a horizontal one (parallel to the arrow that points to the right) and a vertical one (parallel the arrow that points upwards.)

Vector $\sf A$ is horizontal and is at an angle of $0^\circ$ with the horizon.

Horizontal component of vector $\sf A$ : to the right, with a length of $5.00\; \rm m \cdot \cos\left(0^\circ \right) = 5.00\; \rm m$ .
Vertical component of vector $\sf A$ : $5.00\; \rm m \cdot \sin\left(0^\circ \right) = 0\; \rm m$ .

Vector $\sf B$ is at an angle of $30^\circ$ below the horizon.

Horizontal component of vector $\sf B$ : to the right, with a length of $\displaystyle 6.00\; \rm m \cdot \cos\left(30^\circ \right) = (6.00\; \rm m) \times \frac{\sqrt{3}}{2}\approx 5.19615\; \rm m$ .
Vertical component of vector $\sf B$ : downwards, with a length of $\displaystyle 6.00\; \rm m \cdot \sin\left(30^\circ \right) = 6.00\; \rm m \times \frac{1}{2} = 3.00\; \rm m$ .

Calculate the sum of vector $\sf A$ and vector $\sf B$ .

The horizontal component of vector $\sf A$ and vector $\sf B$ are opposite to one another. Therefore, the length of the horizontal component of $\sf (A + B)$ would be the difference between the length of the horizontal components of vector $\sf A\!$ and of vector $\sf B\!$ :

$\displaystyle (6.00\; \rm m) \times \frac{\sqrt{3}}{2} - 5.00\; \rm m \approx 0.196152\; \rm m$ .

The length of the vertical component of vector $\sf A$ is $0\; \rm m$ . Therefore, the length of the vertical component of $\sf (A + B)$ would be equal to the length of the vertical component of vector $\sf B$ , $\displaystyle 6.00\; \rm m \times \frac{1}{2} = 3.00\; \rm m$ .

Therefore, the length of the horizontal and vertical component of $\sf (A + B)$ are approximately $0.196152\; \rm m$ and $3.00\; \rm m$ , respectively. The length of vector $\sf (A + B)\!$ would be approximately:

$\displaystyle \sqrt{(0.196152\; \rm m)^{2} + (3.00\; \rm m)^{2}} \approx 3.01\; \rm m$ .

5 0

3 years ago

Mention & reasons why the ability to adapt to change is

s2008m [1.1K]

Answer:

The ability to adapt is important because :

1) It helps in the survival of human beings.

2) It brings more variation to the human kind.

3) It helps the species from getting endangered or extinct.

4) It brings transformation in the adapting kind.

Hope this helps you☺️☺️

5 0

3 years ago

Three point charges, -4.7 x 10-9 C, -9.7 x 10-9 C, and 7.2 x 10-9 C, are fixed at different positions on a circle. The total ele

irinina [24]

Answer:

Explanation:

q1 = - 4.7 x 10^-9 C

q2 = - 9.7 x 10^-9 C

q3 = 7.2 x 10^-9 C

Potential at the centre of the circle, V = - 1900 V

Let the radius of the circle is r.

So, the potential is given by

$V = \frac{Kq_{1}}{r}+\frac{Kq_{2}}{r}+\frac{Kq_{3}}{r}$

$- 1900 = \frac{9\times 10^{9}}{r}\left ( - 4.7 - 9.7 + 7.2 \right )\times 10^{-9}$

$- 1900 = \frac{-9\times 7.2}{r}$

r = 0.034 m = 3.4 cm

6 0

4 years ago

Contour lines on a topographic map, connect lines with:

Sonbull [250]

Answer:

The same height above sea level.

Explanation:

The distinctive characteristic of a topographic map is the use of elevation contour lines to show the shape of the Earth's surface. Elevation contours are imaginary lines connecting points having the same elevation on the surface of the land above or below a reference surface, which is usually mean sea level.

7 0

3 years ago

A concave mirror of radius of 30cm produces and image three times in size of the object the distance of the object from the mirr

Sloan [31]

$\\ \sf\longmapsto m=\dfrac{-v}{u}$