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Aleonysh [2.5K]
3 years ago
12

Three point charges, -4.7 x 10-9 C, -9.7 x 10-9 C, and 7.2 x 10-9 C, are fixed at different positions on a circle. The total ele

ctric potential at the center of the circle is -1900 V. What is the radius of the circle
Physics
1 answer:
irinina [24]3 years ago
6 0

Answer:

Explanation:

q1 = - 4.7 x 10^-9 C

q2 = - 9.7 x 10^-9 C

q3 = 7.2 x 10^-9 C

Potential at the centre of the circle, V = - 1900 V

Let the radius of the circle is r.

So, the potential is given by

V = \frac{Kq_{1}}{r}+\frac{Kq_{2}}{r}+\frac{Kq_{3}}{r}

- 1900 = \frac{9\times 10^{9}}{r}\left ( - 4.7 - 9.7 + 7.2 \right )\times 10^{-9}

- 1900 = \frac{-9\times 7.2}{r}

r = 0.034 m = 3.4 cm

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Delvig [45]

Answer:

(a) The magnetic energy density in the field is 6.366 J/m³

(b) The energy stored in the magnetic field within the solenoid is 5 kJ

Explanation:

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u _B = \frac{B^2}{2\mu_o} \\\\u _B = \frac{(4)^2}{2(4\pi*10^{-7})}\\\\u_B = 6.366*10^6 \ J/m^3

(b) The energy stored in the magnetic field within the solenoid

U_B = u_B V\\\\U_B = u_B AL

U_B = u_B(A)(L)\\\\U_B = 6.366*10^6(\pi * 0.031^2)(0.26) \\\\U_B = 4997.69 J\\\\U_B = 5 \ KJ\\

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3 years ago
I'd like you to explain this to me, I don't have a clue on how to do this
Westkost [7]

Answer:

Explanation:

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Does this sound familiar?

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Ksju [112]
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