Boys A and B, are pulling a heavy cabinet at the same time with 5 N of force

A cowboy fires a silver bullet with a muzzle speed of 200 m/s into the pine wall of a saloon. Assume all the internal energy gen

tigry1 [53]

Explanation:

KE = q

½ mv² = mCΔT

ΔT = v² / (2C)

ΔT = (200 m/s)² / (2 × 236 J/kg/°C)

ΔT = 84.7°C

8 0

3 years ago

A 0.5 m diameter wagon wheel consists of a thin rim having a mass of 7 kg and six spokes, each with a mass of 1.2 kg. 1.2 kg 7 k

Arte-miy333 [17]

Explanation:

It is given that,

Mass of the rim of wheel, m₁ = 7 kg

Mass of one spoke, m₂ = 1.2 kg

Diameter of the wagon, d = 0.5 m

Radius of the wagon, r = 0.25 m

Let I is the the moment of inertia of the wagon wheel for rotation about its axis.

We know that the moment of inertia of the ring is given by :

$I_1=m_1r^2$

$I_1=7\times (0.25)^2=0.437\ kgm^2$

The moment of inertia of the rod about one end is given by :

$I_2=\dfrac{m_2l^2}{3}$

l = r

$I_2=\dfrac{m_2r^2}{3}$

$I_2=\dfrac{1.2\times (0.25)^2}{3}=0.025\ kgm^2$

For 6 spokes, $I_2=0.025\times 6=0.15\ kgm^2$

So, the net moment of inertia of the wagon is :

$I=I_1+I_2$

$I=0.437+0.15=0.587\ kgm^2$

So, the moment of inertia of the wagon wheel for rotation about its axis is $0.587\ kgm^2$ . Hence, this is the required solution.

4 0

4 years ago

Cosmologist study ____

Firlakuza [10]

The origin and development of the universe

5 0

4 years ago

Read 2 more answers

X rays of wavelength 0.0100 nm are directed in the positive direction of an x axis onto a target containing loosely bound electr

Fofino [41]

Answer:

a) $=4.84*10^{-12}$

b) $= -2.76*10^{-14} J$

c) $i.e -2.76*10^{-14} J$

d)= 0 and the direction of motion is equal to zero

Explanation:

a) compton shift

$\Delta\lambda = \frac{h}{mc} (1-cos\theta)$

$\Delta\lambda = \frac{6.626*10^{-34}}{9.11*10^{-11}3*10^8} (1-cos180)$

$=4.84*10^{-12}$

b) the new wavelength

$\lambda' = 10.0*10^{-12} +4.84^10^{-12}$

$=14.84*10^{-12} m$

$\Delta E = E' - E$

$=hc[\frac{1}{\lambda'}-\frac{1}{\lambda}]$

$\Delta E = 6.626*10^{-34}*(3*10^8)[\frac{1}{14.84*10^{-12}}-\frac{1}{4.8*10^{-12}}]$

$= -2.76*10^{-14} J$

C)By conservation of energy, the kinetic energy of recoiling electron is equal to the magnitude of energy between the photon energy

$i.e -2.76*10^{-14} J$

d) the angle between the positive direction of motion

$sin\phy = \frac{\lambda_t sin\theta}{\lambda'}$

$=\frac{2.43*10^{-12}sin180}{14.84*10^{-12}}$

= 0

the direction of motion is equal to zero.

4 0

4 years ago

Which of the following would increase the amount of electricity generated by a wind turbine

kotykmax [81]

Higher wind speeds would increase the amount of electricity generated by a wind turbine.

<h3>What is a power plant?</h3>

A power plant is an industrial structure that generates electricity. The majority of power plants are linked to the electrical grid.

Stronger winds produce greater power because they enable the blades to revolve more quickly. Greater mechanical and electrical power from the generator result from faster spinning.

Hence, higher wind speeds would increase the amount of electricity generated by a wind turbine.

To learn more about the power plant, refer to the link;

brainly.com/question/7670779

#SPJ1

8 0

2 years ago