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kykrilka [37]
4 years ago
5

If an employer lacked 6 days of working twice as many days as did his employee and the sum of the days they worked is 42, how ma

ny days did each work
Mathematics
1 answer:
alexandr1967 [171]4 years ago
5 0

Answer:

Step-by-step explanation:

2x-6=48

2x=42+6

2x=48days

x=24days

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