What is the equation of a line, in point-slope form, that passes through (-8, 1)and has a slope of ?
1 answer:
Answer:
y-1 = 5(x+8)
Step-by-step explanation:
The standard equation of a line in point slope form is expressed as;
y-y0 = m(x-x0)
m is the slope
(x0, y0) is the point
Given
Slope m = 5 (assumed value)
Point (-8,1)
Substitute the given data's into the formula
y -1 = 5(x-(-8))
y-1 = 5(x+8)
Hence the required equation is y-1 = 5(x+8)
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