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katovenus [111]
3 years ago
5

Who has a higher frequency X-ray or, radio waves?

Chemistry
1 answer:
tester [92]3 years ago
6 0

Answer:

radio waves

Explanation:

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Which type of fertilization is common with animals that live in the water?
Makovka662 [10]

External fertilization in animals usually occurs in water or in damp areas in a process called spawning.

5 0
3 years ago
Read 2 more answers
The equation for the synthesis of ammonia is below. How many moles of H 2 are
kkurt [141]

Moles of H₂ are needed to produce 9.33 moles of NH₃ : 13.995

<h3>Further explanation</h3>

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

The reaction coefficient in a chemical equation shows the mole ratio of the reactants and products

Reaction for the synthesis of ammonia :

N₂+3H₂⇒2NH₃

moles of NH₃ = 9.33

From equation, mol ratio of H₂ : NH₃ = 3 : 2, so mol H₂ :

\tt =\dfrac{3}{2}\times 9.33\\\\=13.995

4 0
3 years ago
How many moles of HCl are found in 500mL of HCl solution with pH of 3​
Alexxx [7]

Answer:

Number of moles = 0.0005 mol.

Explanation:

Given data:

pH = 3

Volume of solution = 500 mL

Number of moles = ?

Solution:

HCl dissociate to gives H⁺ and Cl⁻

HCl → H⁺ + Cl⁻

It is known that,

pH = -log [H⁺]

3 = -log [H⁺]

[H⁺] = 10⁻³ M

[H⁺] = 0.001 M

Number of moles of HCl:

Molarity = number of moles / Volume in litter

Number of moles = Molarity × Volume in litter

Number of moles = 0.001 mol/L × 0.5 L

Number of moles = 0.0005 mol

7 0
4 years ago
I don’t know how to solve this
stepladder [879]
Hi,

Answer is 191.2.

800J = 191.2 cal

Hope this helps.
7 0
3 years ago
How many milliliters of manganese metal, with a density of 7.43 g/mL, would be needed to produce 21.7 grams of hydrogen gas in t
Alla [95]
First compute the number of grams of manganese metal required to make 21.7 grams of H2. 
21.7 g H2 x (1 mole H2/ 2 g H2) x (1 mole Mn/1 mol H2) x (55 grams Mn/1 mol Mn) = 596.75 grams 
Now density = mass/volume 
7.43 = 596.75/volume 
volume = 596.75/7.43 = 80.31 mL 
80.31 mL is the amount of manganese needed.
3 0
3 years ago
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