Answer:
No
Explanation:
as it would stay sticked on them forerver amd a time of 2 months it will kill them
Answer: The "Forchhammer" principle
I hope that this helps you !
Answer:
_2Mg + _O2 --≥2MgO this is balanced
<u>Answer:</u> The mass percent of lead in lead (IV) carbonate is 63.32 %
<u>Explanation:</u>
The given chemical formula of lead (IV) carbonate is 
To calculate the mass percentage of lead in lead (IV) carbonate, we use the equation:

Mass of lead = (1 × 207.2) = 207.2 g
Mass of lead (IV) carbonate = [(1 × 207.2) + (2 × 12) + (6 × 16)] = 327.2 g
Putting values in above equation, we get:

Hence, the mass percent of lead in lead (IV) carbonate is 63.32 %