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Answer:
the standard cell potential value
Explanation:
For every cell, we can calculate its standard electrode potential from the table of standard electrode potentials listed in many textbooks.
However, from Nernst's equation;
Ecell= E°cell - 0.0592/n log Q
Hence the standard cell potential (E°cell) affects the value of the calculated cell potential Ecell from Nernst's equation as stated above.
Answer:
the concentration of new solution = 0.025 M
Explanation:
Given that :
The initial volume V_1 = 15 mL
Initial concentration M_1 = 0.16 M
Final volume V_2 = 95 mL
Final concentration M_2 = ???
We know that M_1 × V_1 = M_2V_2
Making M_2 the subject of the formulae; we have :
M_2 = (M_1 × V_1)/V_2
M_2 = (0.16 × 15)/ 95
M_2 = 0.025 M
Thus, the concentration of new solution = 0.025 M
Based on the above descriptions provided for silicon, I'm assuming that you want to know what silicon is categorized as, in the periodic table, since it posses some properties of metals and nonmetals it would be classified as a mettaloid or a semi metal.
The neutralization reaction is:
Ca(OH)2 + 2HBr ---------- CaBr2 + 2H2O
Therefore based on the reaction stoichiometry, the ratio of Ca(OH)2 : HBr = 1:2
Titration data:
Concentration of HBr = 5.00 *10^-2 M
Volume of HBr required = 48.8 ml = 0.0488 L
# moles of HBr = 5.00 *10^-2 moles L-1 * 0.0488 L = 0.00244 moles
Based on the reaction stoichiometry:
Moles of Ca(OH)2 = 1/2 * Moles of HBr = 1/2 * 0.00244 = 0.00122 moles
Volume of Ca(OH)2 taken = 100 ml = 0.1 L
Concentration of Ca(OH)2 = 0.00122/0.1
= 0.0122 M = 1.22 * 10^-2 M
