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3 years ago

Because Mg and O2 are both elements, no bonds were broken during the formation of MgO.

Chemistry

2 answers:

sladkih [1.3K]3 years ago

5 0

False because this is not true

masya89 [10]3 years ago

4 0

Answer:

false

Explanation

The chemical bonds were broken when creating the compound MgO.

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What type of physical weathering is caused by the expansion of water?

skelet666 [1.2K]

Answer:

wedging

Explanation:

ice or frost wedging

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3 years ago

What determines the amount of chemical energy a substance has?

Ratling [72]

Chemical energy is the kind of energy stored in the bonds formed by atoms and molecules in chemical compounds and elements. This energy is released during a chemical reaction and heat is often given out in the process. These kind of reactions where heat is given out as a by product are called exothermic reactions.

The major factor that determines how much chemical energy a substance has is the mass of that substance. Mass is defined as the amount of matter in a substance.

The higher the mass of a substance, the more concentrated that substance is and subsequently the greater the number of atoms and molecules.

Logically, the higher the number of atoms and molecules then the greater the number of bonds in that substance and subsequently the more the amount of chemical energy stored therein.

6 0

3 years ago

Số oxi hóa của các nguyên tố: Fe(OH)2; Fe(OH)3; FexOy; Zn(OH)2 là gì

BARSIC [14]

Answer:

esfsef

Explanation:

esfsefseF

7 0

2 years ago

Which statement is part of the 3R rule?

makvit [3.9K]

Answer:

The 3R rule states that Radial cracks form a Right angle on the Reverse side of the force. This rule enables an examiner to determine readily the side on which a window or pane of glass was broken.

I hope it's helpful!

7 0

3 years ago

A slender uniform rod 100.00 cm long is used as a meter stick. two parallel axes that are perpendicular to the rod are considere

kvv77 [185]

Refer to the diagram shown below.

The second axis is at the centroid of the rod.
The length of the rod is L = 100 cm = 1 m

The first axis is located at 20 cm = 0.2 m from the centroid.
Let m = the mass of the rod.

The moment of inertia about the centroid (the 2nd axis) is
$I_{g} = \frac{mL^{2}}{12} = (m \, kg) \frac{(1 \, m)^{2}}{12} = \frac{m}{12} \, kg-m^{2}$

According to the parallel axis theorem, the moment of inertia about the first axis is
$I_{1} = I_{g} + (m \, kg)(0.2 m)^{2} \\ I_{1} = \frac{m}{12}+ 0.04m = 0.1233m \, kg-m^{2}$

The ratio of the moment of inertia through the 2nd axis (centroid) to that through the 1st axis is
$\frac{I_{g}}{I_{1}} = \frac{0.0833m}{0.1233m} =0.6756$

Answer: 0.676

6 0

3 years ago

Read 2 more answers