Can anybody help me please???? I'll give brainlest

Você é um comandante de uma espaçonave. Sua missão é chegar até Alfa Centauro em cinco anos. A distância do Sol até Alfa Centaur

Deffense [45]

Answer:

The spaceship will get to Alpha Centaur in time

Step-by-step explanation:

The complete question in English is

You're the commander of a spaceship. Your mission is to reach Alpha Centaur in five years. The distance from the sun to Alpha Centaur is 2.5 x 10^13 miles. The distance from Earth to Sun is approximately 9.3 x 10^7

miles. Your spaceship can travel at the speed of light. You know that light can travel a distance of 5.88 x 10^12 miles in a year. Can you get to Alpha Centaur in time?

step 1

Find the time it takes for the spaceship to travel from Earth to the Sun

The distance from the Earth to Sun is equal to

$9.3*10^7\ miles$

The spaceship can travel at the speed of light

The light can travel a distance of $5.88*10^{12}\ miles$ in a year

so

using a proportion

$\frac{5.88*10^{12}\ miles}{1\ year}=\frac{9.3*10^7\ miles}{x}\\\\x=(9.3*10^7)/5.88*10^{12}\\\\x=1.58*10^{-5} \ years$

This time is very small in years

Convert to minutes

$1.58*10^{-5} \ years=1.58*10^{-5} (365)(24)(60)=8.3\ min$

step 2

Find the time it takes for the spaceship to travel from the Sun to Alpha Centaur

The distance from the the Sun to Alpha Centaur is equal to

$2.5*10^{13}\ miles$

The spaceship can travel at the speed of light

The light can travel a distance of $5.88*10^{12}\ miles$ in a year

so

using a proportion

$\frac{5.88*10^{12}\ miles}{1\ year}=\frac{2.5*10^{13}\ miles}{x}\\\\x=(2.5*10^{13})/5.88*10^{12}\\\\x=4.25\ years$

$4.25\ years< 5\ years$

therefore

The spaceship will get to Alpha Centaur in time

3 0

2 years ago

Please help me please

irina [24]

Answer: YOU WILL NEVER SUCCEED IF YOU DON’T TRY

search it up if you really need help

good luck

6 0

2 years ago

A ball is thrown vertically upward from ground level with an initial velocity of 80 feet per second. The ball's h height after t

Mariulka [41]

Answer:

A

Step-by-step explanation:

It only takes 5 seconds friend.

4 0

3 years ago

Read 2 more answers

The hypotenuse and one of the legs of a right triangle form an angle that has a cosine of square root 2 over 2 . What is the mea

ziro4ka [17]

To answer this question, you can use the values of the unit circle to figure out the angle measurement. Since the cosine is the x value of the circle, we can see that at 45°, the x value is √2/2.
So the missing angle should be 45°

6 0

3 years ago

Solve completely (all missing sides and all missing angles) using trig ratios or laws. Round to the nearest tenth.

hodyreva [135]

Answer:

Step-by-step explanation:

3. Use Cosine law to find the length of the unknown side (PR)

q² = p² + r² - 2prCos Q

q is the opposite side of ∠Q;

p is the opposite side of ∠P; p = 33

r is the opposite sides of ∠R ; r = 67

q² = 33² + 67² - 2* 33*67 Cos 19°

= 1089 + 4489 - 4422 * 0.95

= 1089 + 4489 - 4200.9

= 1377.1

q = √1377.1

q = 37.1

PR = 37.1

To find the angle use law of sin

$\sf \dfrac{q}{Sin \ Q} =\dfrac{p}{Sin \ P}\\\\\\\dfrac{37.1}{Sin \ 19}=\dfrac{33}{Sin \ P} \\\\\\\dfrac{37.1}{0.33}=\dfrac{33}{Sin \ P}\\\\\\37.1* Sin \ P = 33 *0.33\\\\Sin \ P =\dfrac{33*0.33}{37.1}$

Sin P = 0.3

$P = Sin^{-1} 0.3\\$

P = 17.5°

∠R = 180 - (19 + 17.5)

= 143.5°

6 0

2 years ago

Can anybody help me please???? I'll give brainlest​

Can anybody help me please???? I'll give brainlest