Answer:
I think B but im not sure
Explanation:
Answer:
9.8 secs
Explanation:
the ball is in the air so it takes 9.8 secs to get to the ground
According to the Work-Energy Theorem, the work done on an object is equal to the change in the kinetic energy of the object:

Since the car ends with a kinetic energy of 0J (because it stops), then the work needed to stop the car is equal to the initial kinetic energy of the car:

Replace m=1100kg and v=112km/h. Write the speed in m/s. Remember that 1m/s = 3.6km/h:

Therefore, the answer is: 532,346 J.
Is there multiple answer choices?