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vampirchik [111]
3 years ago
5

In a dihybid cross for round and yellow seeds (RrYyxRrYy) what is the probability of having green and wrinkled seeds

Biology
1 answer:
juin [17]3 years ago
5 0

1/16

For a dihybrid cross, the ratio is 9:3:3:1, and green and wrinkled is the one so doing the math, that is 1/16

I hope this helps

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What strengthens and helps to maintain the fluid nature of a cell regardless of temperature?
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Cholesterol in Cell membrane  strengthens and helps to maintain the fluid nature of a cell regardless of temperature

<u>Explanation:</u>

All organisms are made up of one or more cells. Each cell is protected or differentiated by a covering called as the cell membrane. Phospholipids are the basic structure of the cell membrane. Cholesterol prevents the loss of fluid from phospholipids.  

Cell membrane has a lipid layer and cholesterol which is placed between the phospholipids to maintain the fluid nature of the cell under different temperature. Cholesterol prevents the cell from solidifying and helps maintain the fluid. Cholesterol actually acts as a buffer between different temperatures.

3 0
3 years ago
In Drosophila, vestigial (partially formed) wings (vg) are recessive to normal long wings (vg+) and the gene for this trait is a
Marina CMI [18]

Answer/ Explanation:

a. The genotype of a homozygous white eyed long winged female would be Vg+Vg+XrXr. We denote the white allele as recessive (r) because the XY male only has one copy and yet has red eyes, so the red eye trait (R) must be dominant. A homozygous red eyed vestigial winged male would have be VgVgXRY. The possible gametes for the female are Vg+Xr only. For the male, the possible gametes are VgXR or VgY

The attached punnett square shows the results of the cross. The females will all be Vg+VgXRXr. The males will all be Vg+VgXRY (must inherit Y from father). That means they will all  have normal length wings, the males will have white eyes and the females will have red eyes.

b. The F2 flies arise from intercrossing the F1, so the cross will be Vg+VgXRXr x Vg+VgXRY. The possible gametes for the mother are: Vg+XR, Vg+Xr, VgXR or VgXr. The possible gametes for the father are Vg+Xr

, Vg+Y

, VgXr

, VgY

. The attached punnet square shows this cross. The ratio of the phenotypes will be 6:6:2:2, or 3:3:1:1 (long-winged red eye: long-winged white eye: vestigial wing red eye: vestigial wing white eye), genotypes shown in the attachment.

c. F1 cross back to the mother would be Vg+VgXRY x Vg+Vg+XrXr. The genotypes are shown in the attached punnet square. The offspring will all be long-winged with white eyes. The F1 to the father would be Vg+VgXRXr x VgVgXRY. The ratio would be 3:3:1:1 long-winged red eye: long-winged white eye: vestigial wing red eye: vestigial wing white eye

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7 0
3 years ago
Which nitrogenous base is found in RNA but not found in DNA?
GalinKa [24]

Uracil is found in RNA and not DNA. DNA instead has thymine

3 0
3 years ago
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Plants have chloroplasts and mitochondria. What is the purpose of mitochondria when a cell already has chloroplasts?
slega [8]

Answer:

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Explanation:

\bf{ \underline{ \large{Functions \:  of  \: Mitochondria}}}

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\bf{ \underline{ \large{Functions \:  of  \: Chloroplast}}}

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A long string of simple sugars hooked together is called a:
olga55 [171]

Answer:

Strand

Explanation:

8 0
3 years ago
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