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2 years ago

15

A bomb is dropped from a bomber traveling at the speed of 120 km / h, destroying a military objective located at a distance of 2

000 m. How high was the plane traveling?

1 answer:

schepotkina [342]2 years ago

7 0

Answer:

18 km

Explanation:

Convert km/h to m/s:

120 km/h × (1000 m/km) × (1 h / 3600 s) = 33.3 m/s

The time it takes the bomb to travel the 2000 meters is:

2000 m / (33.3 m/s) = 60 s

So it takes 60 seconds for the bomb to fall. The distance it fell is therefore:

Δy = v₀ᵧ t + ½ aᵧ t²

Δy = (0 m/s) (60 s) + ½ (10 m/s²) (60 s)²

Δy = 18,000 m

Δy = 18 km

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3 years ago

An aluminum wire is held between two clamps under zero tension at room temperature. Reducing the temperature, which results in a

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Answer:

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$v=\sqrt{\frac{T}{\mu} }$ ...................................(3)

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Now, equation (3) becomes

$v=\sqrt{\frac{T}{\rho \times A} }$

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$v^2.\rho \times A=A.E\times \frac{\Delta L}{L}$

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