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jonny [76]
3 years ago
7

The method of heat transfer by which the sun warms the earth is

Physics
2 answers:
n200080 [17]3 years ago
8 0
I believe the answer is C) radiation
boyakko [2]3 years ago
4 0
C. Radiation because the sun radiates the water then the water cycle
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How do natural actions such as weathering, erosion, and soil formation affect Earth's surface?
zimovet [89]
There are plates under the surface that shift when there is interruption on the surface <span />
8 0
3 years ago
A. Draw four rays parallel to the optical axis of your mirror. Two above the optic axis and two below it.
Katen [24]

Answer:

   f = q

Explanation:

In the attachment we can see a diagram of the parallel rays.

The dotted line represents the normal to the mirror surface

These rays when reflected using the constructor equation

        \frac{1}{f} = \frac{1}{p} + \frac{1}{q}

where p and q are the distance to the object and the image respectively.

Since the rays are parallel P = inf

          1 / f = 1 / inf + 1 / q

          f = q

this means that all the rays focus on one focal point.

6 0
3 years ago
HELP QUICK!!!
RoseWind [281]
One is for far distance the other is for close range
7 0
3 years ago
Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 9.0 km/h due east. Runner B is initia
sergejj [24]

Answer:

0.176m from the flagpole, westward.

Explanation:

Let the Eastward be the positive direction. So initially runner A is at position -6km, running with velocity of 9km/h while runner B is at position 5km running at a velocity of -8km/h. We can conduct the following equation for their distances over the same time t

s_A = -6 + 9t

s_B = 5 - 8t

When A an B meets, they are at the same position and at the same time. So

s_A = s_B

-6 +9t = 5 - 8t

17t = 5 + 6 = 11

t = 11/17 = 0.647 s

s_A = -6 + 9*0.647 = -0.176 m

So where they meet is 0.176m from the flagpole, westward.

5 0
3 years ago
5.
iris [78.8K]

Answer:

t = 1.659s

Explanation:

We can use the kinematics equations to solve this questions:

v = u + at

v^{2} = u^{2} +2as

where v = Final Velocity, u = initial velocity, a = acceleration, t = time, s = displacement

a) Given information from the question,

u = \frac{70km}{h} =\frac{(70*1000)m}{(1*3600)s} = 19.444m/s (Convert km/h to m/s first)

a = 2m/s^{2}

s = 35m

Now we can substitute these values into the 2nd kinematics equation to find v, final velocity.

v^{2} =(19.444)^{2} +2(2)(35)\\v=\sqrt{(19.444)^{2} +2(2)(35)} \\v= 22.761m/s (5.sf)\\

b) Now we have the final velocity, we can substitute the values into the first kinematics equation to find t , the time taken.

v = u + at

22.761 = 19.444 + 2t

2t = 22.761 - 19.444

t =\frac{22.761-19.444}{2}

t = 1.659s

7 0
2 years ago
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