A bowling ball is traveling at 3 m/s. It starts to roll up a ramp. How high above the ground will the ball be when it stops roll
2 answers:
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If series Rs = R1 + R2
Answer:
A = 1.4 m/s²
B = -0.10493 m/s³
a = 1.29507 m/s²
T = 28095.8271 N
T = 1.13198 W
Explanation:
t = Time taken
g = Acceleration due to gravity = 9.81 m/s²
The equation
Differentiating with respect to time
At t = 0
Hence, A = 1.4 m/s²
B = -0.10493 m/s³
At t = 5 seconds
a = 1.29507 m/s²
T = 28095.8271 N
Weight of rocket
T = 1.13198 W