A bowling ball is traveling at 3 m/s. It starts to roll up a ramp. How high above the ground will the ball be when it stops roll
2 answers:
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So directly the cell density value in a rectangle is:
In this exercise, we must first calculate the area of the rectangle, remembering that you need to convert from nm to cm is:
Next, let's calculate the density from the calculated area:
In this way, the calculation represents that there is:
Learn more: brainly.com/question/18320053
Answer:
<em>The ball will go as high as 8.46 m</em>
Explanation:
<u>Projectile Motion</u>
It's the type of motion that experiences an object launched at a certain height above the ground and moves along a curved path exclusively under the action of gravity.
Being vo the initial speed of the object, θ the initial launch angle, and g the acceleration of gravity, then the maximum height hm can be calculated as follows:
The soccer ball is kicked at a speed of vo=24 m/s at an angle of θ=31°. Taking the value of , then:
The ball will go as high as 8.46 m