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Mashcka [7]
3 years ago
6

A diver rises quickly to the surface from a 5.0 m depth. If she did not exhale the gas from her lunds before rising, by what fac

tor would her lungs expand? Assume the temperature to be constant and the pressure in the lungs to match the pressure outside the diver's body. The density of seawater is 1.03x!0^3 kg.
Physics
1 answer:
Inessa [10]3 years ago
6 0

Answer:

1.5 times

Explanation:

h = depth of the diver initially = 5 m

\rho = density of seawater = 1030 kg m⁻³

P_{i} = Initial pressure at the depth

P_{f} = final pressure after rising = 101325 Pa

Initial pressure at the depth is given as

P_{i} = P_{f} + \rho gh\\P_{i} = 101325 + (1030) (9.8) (5)\\P_{i} = 151795 Pa

V_{i} = Initial volume at the depth

V_{f} = Final volume after rising

Since the temperature remains constant, we have

P_{f} V_{f} = P_{i} V_{i}\\(101325) V_{f} = (151795) V_{i}\\V_{f} = 1.5 V_{i}

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