There are 6.022 × 10²³ atoms in 39.948 g of argon and 4.0026 g of helium.
Explanation:
39.945 g/mole is the molar mass of argon so 39.948 g of argon are equal to 1 mole of argon.
4.0026 g/mole is the molar mass of helium so 4.0026 g of helium are equal to 1 mole of helium.
We know that Avogadro's number tell us the number of particles in 1 mole of substance which is 6.022 × 10²³.
So in 39.948 g of argon and 4.0026 g of helium contains the same number of atoms, 6.022 × 10²³.
Learn more about:
Avogadro's number
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The mass of I₂ that contains 2.57×10²⁵ molecules is 10843.52 g
From a detailed understanding of Avogadro's hypothesis, we understood 1 mole of any substance contains 6.02×10²³ molecules. This implies that 1 mole of I₂ also 6.02×10²³ molecules i.e
<h3>6.02×10²³ molecules = 1 mole of I₂</h3>
Recall:
1 mole of I₂ = 2 × 127 = 254 g
Thus,
<h3>6.02×10²³ molecules = 254 g of I₂</h3>
With the above information, we can obtain the mass of I₂ that contains 2.57×10²⁵ molecules. This is illustrated below:
6.02×10²³ molecules = 254 g of I₂
Therefore,
2.57×10²⁵ molecules = 
<h3>2.57×10²⁵ molecules = 10843.52 g of I₂</h3>
Thus, the mass of I₂ that contains 2.57×10²⁵ molecules is 10843.52 g
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Answer:
6.25 ×10^10 Hz
Explanation:
If the distance between five successive crests is 2.4 cm, then the distance between each crest is 2.4/5 = 0.48 cm or 0.0048 m or 4.8 ×10^-3 m
Since the velocity of a wave is given by;
v= λf
Where;
λ= wavelength of the wave
f= frequency of the wave
But λ= distance between successive crests = 4.8 ×10^-3 m
v= 3×10^8 ms-1 (speed of electromagnetic waves in vacuum)
f= v/λ
f= 3×10^8 ms-1/4.8 ×10^-3 m
f= 0.625 ×10^11 Hz
f= 6.25 ×10^10 Hz
Answer:
78.6 lb/ft³
Step-by-step explanation:
Let's do this in steps.
1. Convert grams to pounds
D = (1.26 g/1 cm³) × (1 lb/454 g)
= 2.775 × 10⁻³ lb/cm³
2. Convert cubic centimetres to cubic feet
D = (2.775 × 10⁻³ lb/1 cm³) × (28 317cm³/1 ft³)
= 78.6 lb/ft³