Answer:
a) I = ( + ) L² , b) w = (\frac{27 M}{18 m} + 2)⁻¹ Lv₀
Explanation:
a) The moment of inertia is a scalar that represents the inertia in circular motion, therefore it is an additive quantity.
The moment of inertia of a rod held at one end is
I₁ = 1/3 M L²
The moment of inertia of the mass at y = L
I₂ = m y²
The total inertia method
I = I₁ + I₂
I = \frac{1}{3} M L² + m (\frac{2}{3} L)²
I = ( + ) L²
b) The conservation of angular momentum, where the system is formed by the masses and the bar, in such a way that all the forces during the collision are internal.
Initial instant. Before the crash
L₀ = I₂ w₀
angular and linear velocity are related
w₀ = y v₀
w₀ = L v₀
L₀ = I₂ y v₀
Final moment. After the crash
= I w
how angular momentum is conserved
L₀ = L_{f}
I₂ y v₀ = I w
substitute
m ()² (\frac{2L}{3} v₀ = ( + ) L² w
m L³ v₀ = ( + ) L² w
m L v₀ = ( + ) w
L v₀ = w
w = (\frac{27 M}{18 m} + 2)⁻¹ Lv₀
Explanation:
For example, when a car travels at a constant speed, the driving force from the engine is balanced by resistive forces such as air resistance and friction in the car's moving parts. ... an object falling at terminal velocity experiences the same air resistance as its weight.
Answer:
Their kinetic energy will increase but potential energy will decrease.
Explanation:
Given that
Initial velocities of electron and proton is zero.
We know that ,electron have negative charge and proton have positive charge it means that they will attract to each other.We know that opposite charge attract to each other and same charge repels to each other.
It means that the velocities of proton and electron will increase and that leads to increase in the kinetic energy of proton and electron.
We know that potential energy U
So when r will decrease then U will increase but in negative direction it means that U will decrease.
So we can say that their kinetic energy will increase but potential energy will decrease.
Answer:
PE = 58.8,J
Explanation:
The potential energy at the top of ramp1 can be found by the application of the formula PE = mgh
Where PE =potential energy
m = mass of block = 2kg
g = acceleration due to gravity = 9.80m/s²
h = height of the top of the ramp from its bottom where the block is initially positioned = 3m
PE = 2×9.8×3 = 58.8J
I believe the term Frequency is what you are looking for.