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Luba_88 [7]
3 years ago
6

To a motorist travelling due North at 50km/hr, the wind appears to come from North West at 60mk/hr. Find the true velocity of th

e wind.​
Physics
1 answer:
kvv77 [185]3 years ago
7 0

Answer:

The true velocity of wind will be 43.1 km/h.

Explanation:

Given that,

Velocity of motor \vec{v_{m}}= 50\hat{j}\ km/h

The resultant velocity of wind

\ver{v_{r}}=60\hat{i}\times\dfrac{1}{\sqrt{2}}+60\hat{j}}\times\dfrac{1}{\sqrt{2}}

Suppose, the true velocity of wind is \vec{v_{w}}.

We need to calculate the true velocity of wind

Using formula of resultant velocity

\vec{v_{m}}+\vec{v_{w}}=\vec{v_{r}}

\vec{v_{w}}=\vec{v_{r}}-\vec{v_{m}}

Where, \vec{v_{m}} = velocity of motor

\vec{v_{w}} = velocity of wind

\vec{v_{r}} = resultant velocity

Put the value into the formula

\vec{v_{w}}=\dfrac{60}{\sqrt{2}}\hat{i}+(\dfrac{60}{\sqrt{2}}-50)\hat{j}

\vec{v_{w}}=42.43\hat{i}-7.57\hat{j}

The magnitude of true velocity is,

v_{m}=\sqrt{(42.43)^2+(-7.57)^2}

v_{m}=43.0.9\approx 43.1\ km/h

Hence,  The true velocity of wind will be 43.1 km/h.

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on a recent adventure trip, Anita Break went rock climbing. Anita was able to perform 1370 J of work in 100 seconds. Determine A
Zanzabum

        Power = (energy) / (time)

         =    (1370 joules) / (100 seconds)

         =       13.7  joules/second

         =       13.7 watts .

That's not an awful lot of power, especially for a strenuous activity like
rock-climbing.  Shoot !  Even I could probably perform at that level.

Compare 13.7 watts to the light power coming out of a 20-watt night light.

         13.7 watts  =  0.018 horsepower.      (rounded)
5 0
3 years ago
Peter designed a road with a curve of radius 30 m that is banked so that a 950 kg car traveling at 40.0 km/h can round it even i
spayn [35]

Answer:

v = 15.56 m/s

v = 56 km/h

Explanation:

When coefficient of friction is approximately zero then we have

F_ncos\theta = mg

F_n sin\theta = \frac{mv^2}{R}

tan\theta = \frac{v^2}{Rg}

here we know that

v = 40 km/h = 11.11 m/s

R = 30 m

tan\theta = \frac{11.11^2}{30\times 9.81}

\theta = 22.75 degree

now when friction coefficient is 0.30 then we have

F_n cos\theta = mg + F_f sin\theta

F_f cos\theta + F_n sin\theta = \frac{mv^2}{R}

now we have

v = \sqrt{Rg(\frac{\mu + tan\theta}{1 - \mu tan\theta})}

v = \sqrt{30(9.81)(\frac{0.30 + tan22.75}{1 - (0.30) tan22.75})}

v = 15.56 m/s

v = 56 km/h

3 0
3 years ago
A tow truck drags a stalled car along a road. The chain makes an angle of 30???? with the road and the tension in the chain is 1
My name is Ann [436]

Answer: work = 1,305kJ

Explanation:

angle= 30°

force= 1,500N

distance= 1,000m

The formula for work is : Work= force x distance, however there is an angle of 30° between the direction of force applied and the direction of motion, therefore force must be decomposed to its value on the horizontal axis which is the direction of motion by using the cosine of the very angle.

W= F×cos(α)×D

W= 1,500×cos (30)×1,000

W= 1,305kJ ( kilojoules)

3 0
3 years ago
A student grabs a piece of paper and tears it from the middle. Which statement best explains the forces involved?
PolarNik [594]

Answer:

b. The normal force between the molecules of the paper is overcome by the contact force of the hands.

Explanation:

The paper molecules are held together by a weak bond. When the student holds the paper on both sides with the center of the paper in between, the student applies two equal forces in the opposite direction of the paper making the paper molecules weaken and separate.

3 0
3 years ago
Read 2 more answers
The six statements below represent Newton's three laws of motion and Kepler's three laws of planetary motion. Match each stateme
mote1985 [20]

Answer:

1. Force = mass x acceleration - Newton

2. A planet moves faster in the part of its orbit nearer the Sun and slower when farther from the Sun, sweeping out  equal areas in equal times - Kepler

3. For any force, there is an equal and opposite reaction force - Newton .

4. An object moves at constant velocity if there is no net force acting upon it - Newton

5. The orbit of each planet about the Sun is an ellipse with the Sun at one focus  - Kepler.

6. More distant planets orbit the Sun at slower average speeds, obeying the precise mathematical relationship p2-a3 - Kepler.

Explanation:

The three laws of planetary motion formulated by Johannes Kepler or Kepler's laws of planetary motion:

  1. The first law states that the planets move around the Sun in an elliptical orbit with the Sun at one of the foci.
  2. The second law states that the line segment joining a planet to the Sun sweeps out equal areas in equal time.
  3. The third law states that the square of the orbital period (p) of a planet is directly proportional to the cube of the mean distance (a) from the Sun (or semi-major axis of its orbit) i.e., p² is proportional to a³.

The three laws of motion formulated by Sir Isaac Newton or Newton's laws of motion:

  1. The first law, also known as the law of inertia states that an object at rest or moves at a constant velocity will remain at rest or keep moving at a constant velocity unless it is acted upon by a force.
  2. The second law states that the total force (F) applied on an object is directly related to the acceleration (a) of that object produced by the applied force and the mass (m) of the object, i.e., F = ma (assuming the mass m is constant).
  3. The third law, also known as the law of action and reaction states that when an object exerts a force on another object, then the latter exerts a force equal in magnitude and opposite in direction on the former object i.e., for every action, there is an equal and opposite reaction. The example includes the recoiling of a gun when it fires a bullet forward.
5 0
3 years ago
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