Answer:
no..
Explanation:
in balanced force it will or in this case u would stay still or u would move at the same speed.. but when u jumps the speed changes..so this is an unbalanced force
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Answer:
r = 4.44 m
Explanation:
For this exercise we use the Archimedes principle, which states that the buoyant force is equal to the weight of the dislodged fluid
B = ρ g V
Now let's use Newton's equilibrium relationship
B - W = 0
B = W
The weight of the system is the weight of the man and his accessories (W₁) plus the material weight of the ball (W)
σ = W / A
W = σ A
The area of a sphere is
A = 4π r²
W = W₁ + σ 4π r²
The volume of a sphere is
V = 4/3 π r³
Let's replace
ρ g 4/3 π r³ = W₁ + σ 4π r²
If we use the ideal gas equation
P V = n RT
P = ρ RT
ρ = P / RT
P / RT g 4/3 π r³ - σ 4 π r² = W₁
r² 4π (P/3RT r - σ) = W₁
Let's replace the values
r² 4π (1.01 10⁵ / (3 8.314 (70 + 273)) r - 0.060) = 13000
r² (11.81 r -0.060) = 13000 / 4pi
r² (11.81 r - 0.060) = 1034.51
As the independent term is very small we can despise it, to find the solution
r = 4.44 m
Answer:
It spins on the side where it looks shiny.
Explanation:
I believe the answer is the second one.
Answer:
ΔU= 1.3922 KJ
Explanation:
Given that
Q= 2 KJ
Note- 1 .Heat added to the system taken as positive and heat leaving from the system is taken negative.
2. Work done on the system taken as negative and work done by the system taken as positive.
P =2 atm
V₁= 2 L
V₂=5 L
Work done by the gas W
W= P ( V₂- V₁)
W= 2 ( 5 - 2)
W= 6 atm.L
1 L·atm = 0.1013 kJ
W= 0.6078 KJ
From first law of thermodynamics
Q= W + ΔU
ΔU=Change in internal energy
2 = 0.6078 + ΔU
ΔU= 1.3922 KJ