The average velocity of the whole journey will be total distance covered divided by the total time. It will be approximately equal to 8 m/s. The right answer is option B
<h2>VELOCITY</h2>
Velocity is the distance travelled in a specific direction. While the average velocity of the whole journey will be total distance covered divided by the total time
When driving a Toyota avensis car along a straight road for 16.5km at
50km/h,
The velocity = 50 km/h
Distance = 16.5 km
Use the speed formula to calculate time.
Speed = distance / time
Time = distance / speed
Time = 16.5 / 50
Time = 0.33 s
If over the next 20min, you walked another 2.5km further along the road for a petrol station, Then,
average velocity = Total distance covered divided by total time taken.
Where
The time t = 20/60 = 0.333 h
Total time = 0.33 + 0.3333
Total time = 0.6633333
Total distance = 16.5 + 2.5
Total distance = 19 km
Average velocity = 19 / 0.66333
Average Velocity = 28.64 km/h
Now convert Km/h to m/s
(28.6432 x 1000) / 3600
286432 / 3600
7.956m/s
Therefore, the average velocity of the whole journey from beginning of the drive to the arrival at the filling station will be approximately 8 m/s
Learn more about velocity here: brainly.com/question/6504879
Answer:
14.4kJ
Explanation:
Work = Force x distance
W × h = mgh
Given that,
mass m, = 59.5kg
acceleration due to gravity = 9.8m/s^2
height ,h = 16.2cm
convert to m is 0.162m
How much work = m x g x h
height is 0.162 x 152 steps
h = 24.624m
work = 59.5 x 9.8 x 24.624
= 14,358.25Joule
= 14.4kJ
Complete Question
Q. Two go-carts, A and B, race each other around a 1.0km track. Go-cart A travels at a constant speed of 20m/s. Go-cart B accelerates uniformly from rest at a rate of 0.333m/s^2. Which go-cart wins the race and by how much time?
Answer:
Go-cart A is faster
Explanation:
From the question we are told that
The length of the track is 
The speed of A is 
The uniform acceleration of B is 
Generally the time taken by go-cart A is mathematically represented as
=> 
=> 
Generally from kinematic equation we can evaluate the time taken by go-cart B as
given that go-cart B starts from rest u = 0 m/s
So
=> 
=> 
Comparing 
we see that 
is smaller so go-cart A is faster
Answer: it goes the same speed as the car
Explanation:
