Answer:
a= 92. 13 m/s²
Explanation:
Given that
Amplitude ,A= 0.165 m
The maximum speed ,V(max) = 3.9 m/s
We know that maximum velocity in the SHM given as
V(max) = ω A
ω=Angular speed
A=Amplitude
ω=23.63 rad/s
The maximum acceleration given as
a = ω² A
a= (23.63)² x 0.165 m/s²
a= 92. 13 m/s²
Therefore the maximum magnitude of the acceleration will be 92. 13 m/s².
Answer:
The value is
Explanation:
From the question we are told that
The length of the crack is
The frequency is
The distance outside the cave that is being consider is
The speed of sound is
Generally the wavelength of the wave is mathematically represented as
=>
=>
Generally for a single slit the path difference between the interference patterns of the sound wave and the center is mathematically represented as
=>
=>
Generally the width of the sound beam is mathematically represented as
=>
=>
Here, as the charge is uniformly distributed in the sphere, we will consider s as an area of the sphere which is, s=4πr2 and r is radius of the gaussian surface shown in the figure above. From this, it can be seen that
Good conductors can give us more electrical energy. Advanced batteries today use ion charges for the batteries.