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2 years ago

a current of 180 mini amphere passes through a conductor for 5minute calculate the quantity of electricity transported

Physics

1 answer:

oksano4ka [1.4K]2 years ago

8 0

Answer:

Explanation:

You can calculate the total electric charge that passes through the conductor as $q=It=(180\times 10^{-3})(5\times 60)= 54 C$ . It means that the number of electron that passes through the conductor is:

$n=\frac{q}{e}=\frac{54}{1.6\times 10^{-19}}=33.75\times 10^{19}$

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When a warm air mass collides with a cold air mass, the warm air mass rises above the cold air mass leading too:

nikdorinn [45]

Answer: It leads to a front. A front is.., I don't know how to explain it, so I'll add a picture. Fronts are made out of clouds and usually bring rain. So the answer is C: The formation of clouds and rain.

Explanation:

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3 years ago

A student calculates the density of a copper cube to be 4.15 g/cm . If the accepted value is 8.64 g/cm the percentage error in h

Helen [10]

The percentage error in his experimental value is -51.97%.

<h3>What is percentage error?</h3>

This is the ratio of the error to the actual measurement, expressed in percentage.

To calculate the percentage error of the student, we use the formula below.

Formula:

Error(%) = (calculated value-accepted value)100/(accepted............. Equation 1

From the question,

Given:

Calculated value = 4.15 g/cm
accepted value = 8.64 g/cm

Substitute these values into equation 1

Error(%) = (4.15-8.64)100/8.64
Error(%) = -4.49(100)/8.64
Error(%) = -449/8.64
Error(%) = -51.97 %

Hence, The percentage error in his experimental value is -51.97%.

Learn more percentage error here: brainly.com/question/5493941

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3 years ago

A wind turbine is rotating counterclockwise at 0.626 rev/s and slows to a stop in 12.9 s. Its blades are 17.9 m in length. What

iogann1982 [59]

Answer:

276.5 m/s^2

Explanation:

The initial angular velocity of the turbine is

$\omega=0.626 rev/s \cdot 2\pi rad/rev =3.93 rad/s$

The length of the blade is

r = 17.9 m

So the centripetal acceleration is given by

$a=\omega^2 r$

At the instant t = 0,

$\omega=3.93 rad/s$

So the centripetal acceleration of the tip of the blades is

$a=(3.93 rad/s)^2 (17.9 m)=276.5 m/s^2$

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3 years ago

Distance and amount of charge are factors that determine which of the following quantities?

lorasvet [3.4K]

The distance between charged objects, the quantity of charge on them,
and the polarity of their charges, are the factors that determine the strength
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3 years ago

The radioactive 60co isotope is used in nuclear medicine to treat certain types of cancer. Calculate the wavelength and frequenc

Ivanshal [37]

1. Frequency: $3.23\cdot 10^{20} Hz$

The energy given is the energy per mole of particles:

$E=1.29\cdot 10^{11} J/mol$

1 mole contains a number of Avogadro of particles, $N_A$ , equal to

$N_A=6.022\cdot 10^{23}$ particles

So, by setting the following proportion, we can calculate the energy of a single photon:

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