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zhuklara [117]
3 years ago
8

CO + 7H2 - C3Hg + 3H20

Physics
1 answer:
Assoli18 [71]3 years ago
6 0

Answer:

Espanol 7h2 that's c coupon

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Hoochie [10]

Answer:

compressional wave

Explanation:

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3 years ago
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HEY CAN ANYONE PLS PLS ANSWER DIS I RLY NEED IT
jeka94
Place the object in an electronic balance and measure its mass.
Place a measured amount of water in the cylinder.
Place the object in the cylinder so that it’s fully submerged.
Measure the new level of the liquid and subtract the original level. This is equal to the volume of the object.

Density = mass / volume.
8 0
4 years ago
A pool is 31.4 m long and 40.0 m wide. if the average depth of water is 3.30 ft, what is the mass (in kg) of water in the pool?
olga nikolaevna [1]

The mass (in kg) of water in the pool is 1.264 * $$10^6 kg.

<h3>What is mass?</h3>

A numerical measurement of inertia, a basic characteristic of all matter, in physics. It essentially refers to a body of matter's resistance to changing its speed or location in response to the application of a force. The change caused by an applied force is smaller the more mass a body has.

Mass is a physical body's total amount of matter. Inertia, or the body's resistance to acceleration when a net force is applied, is also measured by this term. The strength of an object's gravitational pull to other bodies is also influenced by its mass. The kilogram serves as the SI's fundamental mass unit.

Given: A pool is 31.4 m long and 40.0 m wide. if the average depth of water is 3.30 ft

31.4 * 40.0 = 1256 $$m^2

1 m = 39.37 in = 3.28 ft

3.30 ft = 1.01 m

Volume of pool = 1256 * 1.01 = 1264 $$m^3

Since 1 $$m^3 water contains $$10^3$ kg the volume of the pool is

1.264 E3 * E3 = 1.264E6 kg

(or 1.264 * $$10^6 kg)

The mass (in kg) of water in the pool is 1.264 * $$10^6 kg.

To learn more about mass refer to:

brainly.com/question/19385703

#SPJ4

8 0
2 years ago
A food web is shown below. Hawk Fox Snake Mouse Frog Grasshopper Beetle Fungus Grass Which organisms could be both predators and
xxTIMURxx [149]

Answer:

A

A fox and hawk can be both a predator and prey

8 0
3 years ago
An amateur player is about to throw a dart with an initial velocity of 15 meters/second onto a dartboard that is at a distance o
Minchanka [31]

Answer:

B. 0.16 m

Explanation:

The vertical distance by which the player will miss the target is equal to the vertical distance covered by the dart during its motion.

Since the dart is thrown horizontally, the initial vertical velocity is zero:

v_y = 0

While the horizontal velocity is

v_x = 15 m/s

The horizontal distance covered is

d_x = 2.7 m

Since the dart moves by uniform motion along the horizontal direction, the time it takes for covering this distance is

t=\frac{d_x}{v_x}=\frac{2.7 m}{15 m/s}=0.18 s

along the vertical direction, the motion is a uniformly accelerated motion with constant downward acceleration g=9.8 m/s^2, so the vertical distance covered is given by

d_y = \frac{1}{2}gt^2=\frac{1}{2}(9.8 m/s^)(0.18 s)^2=0.16 m

8 0
4 years ago
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