How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is 3.33×10−21 n
1 answer:
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Answer:
<em>3924 Pa</em>
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Explanation:
Volume of cylinder = 2 L = 0.002 m^3 (1000 L = 1 m^3)
diameter of the inner cylinder = 8 cm = 0.08 m (100 cm = 1 m)
radius of the inner cylinder = diameter/2 = 0.08/2 = 0.04 m
area of the inner cylinder =
where = 3.142,
and r = radius = 0.04 m
area of inner cylinder = 3.142 x = 0.005 m^2
<em>height h of the water in this cylinder = volume/area</em>
h = 0.002/0.005 = 0.4 m
<em>pressure at the bottom of the cylinder due to the height of water = pgh</em>
where
p = density of water = 1000 kg/m^3
g = acceleration due to gravity = 9.81 m/s^2
h = height of water within this cylinder = 0.4 m
pressure = 1000 x 9.81 x 0.4 = <em>3924 Pa</em>
Answer: An 8 kg book at a height of 3 m has the most gravitational potential energy.
Explanation:
Gravitational potential energy is the product of mass of object, height of object and gravitational field.
So, formula to calculate gravitational potential energy is as follows.
U = mgh
where,
m = mass of object
g = gravitational field =
h = height of object
(A) m = 5 kg and h = 2m
Therefore, its gravitational potential energy is calculated as follows.
(B) m = 8 kg and h = 2 m
Therefore, its gravitational potential energy is calculated as follows.
(C) m = 8 kg and h = 3 m
Therefore, its gravitational potential energy is calculated as follows.
(D) m = 5 kg and h = 3 m
Therefore, its gravitational potential energy is calculated as follows.
Thus, we can conclude that an 8 kg book at a height of 3 m has the most gravitational potential energy.