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zavuch27 [327]
3 years ago
5

How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is 3.33×10−21 n

?
Physics
1 answer:
qwelly [4]3 years ago
4 0

Answer:

The number of excess electrons on each sphere is 759

Explanation:

Given that,

distance , d = 20 cm

                    = 0.20 m

let the number of electrons is n  

Electric force (F) = k × (n × e)² /d²

3.33 × 10^{-21} = 9 × 10^{9} × (n × 1.602 × 10^{-19})² /0.2²

solving for n

n = 759

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If the mass of an object i if the mass of an object is 44 kg in its velocity is 10 m/s East how much kinetic energy
vampirchik [111]
K=0.5 mu×u
K=2200J no matter the direction
8 0
3 years ago
Question 4 - If Angelica starts out at 30m/s, and in 16 s speeds up to 84 m/s, what is her acceleration?
Triss [41]

Answer:

C. 3.375 m/s^2

Explanation:

The acceleration of an object can be found using the equation:

a=\frac{v-u}{t}

where

v is the final velocity

u is the initial velocity

t is the time it takes for the velocity to change from u to v

In this problem:

u = 30 m/s is the initial velocity of Angelica

v = 84 m/s is the final velocity

t is the time

Substituting into the equation, we find the acceleration:

a=\frac{84-30}{16}=3.375 m/s^2

4 0
3 years ago
In this example we will analyze the forces acting on your body as you move in an elevator. Specifically, we will consider the ca
dexar [7]

Answer:

The reading of the scale during the acceleration is 446.94 N

Explanation:

Given;

the reading of the scale when the elevator is at rest = your weight, w = 600 N

downward acceleration the elevator, a = 2.5 m/s²

The reading of the scale can be found by applying Newton's second law of motion;

the reading of the scale  = net force acting on your body

R = mg + m(-a)

The negative sign indicates downward acceleration

R = m(g - a)

where;

R is the reading of the scale which is your apparent weight

m is the mass of your body

g is acceleration due to gravity, = 9.8 m/s²

m = w/g

m = 600 / 9.8

m = 61.225 kg

The reading of the scale is now calculated as;

R = m(g-a)

R = 61.225(9.8 - 2.5)

R = 446.94 N

Therefore, the reading of the scale during the acceleration is 446.94 N

4 0
2 years ago
You have a string with a mass of 0.0135 kg. You stretch the string with a force of 8.29 N, giving it a length of 1.83 m. Then yo
Sphinxa [80]

The wavelength of the standing wave at fourth harmonic is; λ = 0.985 m and the frequency of the wave at the calculated wavelength is; f = 36.84 Hz

Given Conditions:

mass of string; m = 0.0133 kg

Force on the string; F = 8.89 N

Length of string; L = 1.97 m

1. To find the wavelength at the fourth normal node.

At the fourth harmonic, there will be 2 nodes.

Thus, the wavelength will be;

λ = L/2

λ = 1.97/2

λ = 0.985 m

2. To find the velocity of the wave from the formula;

v = √(F/(m/L)

Plugging in the relevant values gives;

v = √(8.89/(0.0133/1.97)

v = 36.2876 m/s

Now, formula for frequency here is;

f = v/λ

f = 36.2876/0.985

f = 36.84 Hz

Read more about Harmonics of standing waves at; brainly.com/question/10274257

#SPJ4

7 0
1 year ago
Focus Question: How are physical properties used to compare and classify substances?​
Kisachek [45]

Answer:

Properties that can be determined without changing the composition of a substance are referred to as physical properties. Characteristics such as melting point, boiling point, density, solubility, color, odor, etc. ... Physical and chemical properties can be used to classify a substance as ionic or molecular.

Explanation:

Hope it helps! Correct me if I am wrong!

Dont worry im sure about my answer!

If you dont mind can you please mark me as brainlest?

Its ok if you don't want to!

8 0
3 years ago
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