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zavuch27 [327]
4 years ago
5

How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is 3.33×10−21 n

?
Physics
1 answer:
qwelly [4]4 years ago
4 0

Answer:

The number of excess electrons on each sphere is 759

Explanation:

Given that,

distance , d = 20 cm

                    = 0.20 m

let the number of electrons is n  

Electric force (F) = k × (n × e)² /d²

3.33 × 10^{-21} = 9 × 10^{9} × (n × 1.602 × 10^{-19})² /0.2²

solving for n

n = 759

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