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Anarel [89]
3 years ago
12

Gravity is a force that pulls things

Physics
1 answer:
Katena32 [7]3 years ago
8 0

Answer:

down and towards it

Explanation:

just because it is man

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A girl is delivering newspapers travels 3 km north, 3 km west and 5 km south. What is the total distance that she travels?
UNO [17]

She travels 11 km

I hope I helped

:D

6 0
4 years ago
Read 2 more answers
What is the maximum speed with which a 1200-kg car can round a turn of radius 88.0 m on a flat road if the coefficient of static
boyakko [2]

Answer:

18.6 m/s

Explanation:

The frictional force acting on the car is given by:

F_f = \mu m g=(0.40 )(1200 kg)(9.81 m/s^2)=4709 N

But the frictional force also corresponds to the centripetal force that keeps the car in circular motion in the turn:

F_f = F_c = m \frac{v^2}{r}

Where v is the maximum speed the car can achieve remaining in the turn. Substituting r=88.0 m and re-arranging the formula, we can find the value of v:

v=\sqrt{\frac{Fr}{m}}=\sqrt{\frac{(4709 N)(88.0 m)}{1200 kg}}=18.6 m/s

6 0
3 years ago
A parachuter, falling with a constant speed, drops 456m in 14.4s.
monitta

Answer:

The parachuter is falling at a speed of 31.667 meters per second.

Explanation:

Given that parachuter falls at constant speed and travelled distance and time are known, the unknown is speed, measured in meters per second, which is obtained by the following kinematic expression:

s = \frac{d}{t}

Where:

d - Travelled distance, measured in meters.

t - Time, measured in seconds.

If d = 456\,m and t = 14.4\,s, the speed of the parachuter is:

s = \frac{456\,m}{14.4\,s}

s = 31.667\,\frac{m}{s}

The parachuter is falling at a speed of 31.667 meters per second.

3 0
3 years ago
Please Help ASAP I Need Help with question 5 I got the answer wrong this is my second and final attempt for the unit test
victus00 [196]
The answer is Electrical
8 0
3 years ago
Read 2 more answers
Help help help help help
nalin [4]
I am not sure on the rest but the answer to question 4 is volts. sorry i couldn’t be of more help!
3 0
3 years ago
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