1. Velocity at which the packet reaches the ground: 121.2 m/s
The motion of the packet is a uniformly accelerated motion, with constant acceleration
directed downward, initial vertical position
, and initial vertical velocity
. We can use the following SUVAT equation to find the final velocity of the packet after travelling for d=750 m:

substituting, we find

2. height at which the packet has half this velocity: 562.6 m
We need to find the heigth at which the packet has a velocity of

In order to do that, we use again the same SUVAT equation substituting
with this value, so that we find the new distance d that the packet travelled from the helicopter to reach this velocity:

Which means that the heigth of the packet was

Answer:
the angular acceleration of the car is 1.5 rad/s²
Explanation:
Given;
initial angular velocity,
= 10 rad/s
final angular velocity,
= 25 rad/s
time of motion, t = 10 s
The angular acceleration of the car is calculated as follows;

Therefore, the angular acceleration of the car is 1.5 rad/s²
Longitudinal, because the sound can only travel at one direction
Im pretty sure its C- Wavelength