Question:
A 63.0 kg sprinter starts a race with an acceleration of 4.20m/s square. What is the net external force on him? If the sprinter from the previous problem accelerates at that rate for 20m, and then maintains that velocity for the remainder for the 100-m dash, what will be his time for the race?
Answer:
Time for the race will be t = 9.26 s
Explanation:
Given data:
As the sprinter starts the race so initial velocity = v₁ = 0
Distance = s₁ = 20 m
Acceleration = a = 4.20 ms⁻²
Distance = s₂ = 100 m
We first need to find the final velocity (v₂) of sprinter at the end of the first 20 meters.
Using 3rd equation of motion
(v₂)² - (v₁)² = 2as₁ = 2(4.2)(20)
v₂ = 12.96 ms⁻¹
Time for 20 m distance = t₁ = (v₂ - v ₁)/a
t₁ = 12.96/4.2 = 3.09 s
He ran the rest of the race at this velocity (12.96 m/s). Since has had already covered 20 meters, he has to cover 80 meters more to complete the 100 meter dash. So the time required to cover the 80 meters will be
Time for 100 m distance = t₂ = s₂/v₂
t₂ = 80/12.96 = 6.17 s
Total time = T = t₁ + t₂ = 3.09 + 6.17 = 9.26 s
T = 9.26 s
Answer:
The cable used is a straight through cable.
Explanation:
The cable used here is a straight through cable, that is why it fails to establish the connection.
Cross-over cables are used to communicate over legacy switch. It is used to connect computing devices directly.
In a cross over cable, signal gets transmit from one end of the device to the other.
Initial momentum = 0.15 kg * (-5 m/s) = - 0.75 N*s
final momentum = 0.15 * ( 3 m/s) = 0.45 N*s
Change in momentum = final momentum - initial momentun =
= 0.45N*s - (- 0.75N*s) = 1.2 N*s
Answer: 1.2 N*s
Answer:
(A) 12.222 ohm (B) 990 W
Explanation:
We have given the voltage of the heating element V = 110 V
The current in the heating element i = 9 A
(a) According to ohm's law V =iR
So 

(b) The power dissipated in the resistor is given by
So the power dissipated = 990 W
Answer:
(a) Moon has smaller diameter and lower density than earth
Explanation:
Moon has smaller diameter than earth earth has a diameter of 12742 km whereas moon has a diameter of 3474.21 km
So for density density is given by 
From the relation we can see that density is dependent on mass and volume directly proportional to mass and inversely proportional to diameter
But in case of earth and moon mass is more dominating than volume so density is less for moon than earth