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victus00 [196]
3 years ago
13

Calculate the amount of work done to draw a current of 8A from a point at 100V to a point at 120V in 2 seconds?

Physics
1 answer:
Morgarella [4.7K]3 years ago
3 0
Given:
I=8A
t=2second
Potential difference,V=120-100=20volt
Workdone=V×i×t
=20×8×2
=320 joule.
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\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

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1 mole of cesium contains atoms =  6.023\times 10^{23}

0.102 moles of cesium contains atoms =  \frac{6.023\times 10^{23}}{1}\times 0.102=0.614\times 10^{23}

The relation of atoms with time for radioactivbe decay is:

N_t=N_0\times \frac{1}{2}^{\frac{t}{t_{\frac{1}{2}}}}

Where N_t =atoms left undecayed

N_0 = initial atoms

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Amount of particles that decay is  = 0.614\times 10^{23}\times 1.32\times 10^{-7}=0.81\times 10^{16}

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