Step-by-step explanation:
2sin(x)cos(x) - sin(x) + 2cos(x)-1= 0
<=> sinx( 2cosx -1) + ( 2cosx -1) =0
<=> (sinx +1) + ( 2cosx-1)=0
<=> sinx=-1 or cosx= 1/2
+) sinx=1 => x= pi/2 + k×2pi
+)cosx=1/2 => x= pi/3+ k×2pi or x=-pi/3 + k×2pi
x€ [0,2pi] => x= pi/2, pi/3.
Answer:
the last one is the answer!
Answer:
are there any answer choices?
Following rules of logs, we can do the following:
log x^4 - log y^(1/2) + log z^3
Combine the first and 3rd factors to get log [x^4*z^3]
Seeing that the neg. sign signifies division, write this new term - log y^(1/2) as a quotient:
[x^4*z^3]
log ----------------
y^(1/2)
Next time, please include the instructions when you present your problem.
Thx.
