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Kitty [74]
2 years ago
13

For 22 days out of the month, Brian rides his bike 16 miles a day. About how many miles does Brian ride in one month? Solve the

problem and explain how you estimated the product.
Mathematics
1 answer:
Minchanka [31]2 years ago
8 0
352 would be the answer I think I multiplied it and searched it up to make sure I was right
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Anyone know the answer i don’t need the steps or the work just the answer. ty!
NeX [460]

Answer:

= x^4 y^5 / 3

Step-by-step explanation:

I got this answer  = x^4 y^5 / 3

But my answer is not found directly

And I think they deliberately set up this arrangement to make us mess up

, but in your Options I think it's ( B )

7 0
2 years ago
Faelyn grouped the terms and factored the GCF out of the groups of the polynomial 6x4 – 8x2 + 3x2 + 4. Her work is shown. Step 1
fiasKO [112]

Answer:

B. Faelyn should realize that her work shows that the polynomial is prime

Step-by-step explanation:

The polynomial 6x⁴ – 8x² + 3x² + 4 needs to be factored and the steps are:

Step 1: (6x⁴ – 8x²) + (3x² + 4)

Step 2: 2x²(3x² – 4) + 1(3x² + 4)

Since they do not have a common factor, Faelyn should realize that her work shows that the polynomial is prime. A prime polynomial cannot be factored further because it is at its lowest common term and cannot be factored into any other polynomial of a lower degree. Prime polynomials have integer coefficients. A prime polynomial is also referred to as an irreducible polynomial.

6 0
2 years ago
A traffic engineer monitors the rate at which cars enter the main highway during the afternoon rush hour. From her data she esti
sertanlavr [38]

Answer:

On average, cars enter the highway during the first half hour of rush hour at a rate 97 per minute.

Step-by-step explanation:

Given that, the rate R(t) at which cars enter the highway is given the formula

R(t)= 100(1-0.0001t^2)

The average rate of car enter the highway during first half hour of rush hour is the average value of R(t) from t=0 to t=30.

\therefore \int_0^{30}  100(1-0.0001t^2)\ dt

=[100(t-0.0001\frac{t^3}{3})]_0^{30}

=100[(30-0.0001\frac{30^3}{3})-(0-0.0001\frac{0^3}{3})]

=2901

The average rate of car is =\frac{\textrm{The number of car}}{Time}

                                           =\frac{2910}{30}

                                          =97

On average, cars enter the highway during the first half hour of rush hour at a rate 97 per minute.

8 0
3 years ago
2-x=-3(x+4)+6 please help
MariettaO [177]

Answer:

2-x=-3x-12+6

2-x=-3x-6

8=-3x+x

8=-2x

x=-4

hope it's clear

mark me as brainliest

6 0
3 years ago
Read 2 more answers
Find the GCF. 14abc and 28 a 2 b 2 c 3
9966 [12]
4 because 14abc would equal 108 the factors of 108 are 1,2,3,4,6,9,12,18,27,36,54,108 the factors of 28 are 1,2,4,7,14,28 so it's 4
7 0
3 years ago
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