Complete question:
It is measured that 3/4 of a body's volume is submerged in oil of density 800kg/m³. What is the specific gravity of oil?
Answer:
The specific gravity of the oil is 0.8.
Explanation:
Given;
density of the oil, 
= 800 kg/m³
density of water, 
= 1000 kg/m³
The specific gravity of any substance is the ratio of the substance density to the density of water.
Specific gravity of the oil = density of the oil / density of water
Specific gravity of the oil = 800/1000
Specific gravity of the oil = 0.8
Therefore, the specific gravity of the oil is 0.8.
Here, you need to use your "Protractor" as it is given in the question, but we can calculate the value with the help of our mathematical calculation too:
[ Protractor can be use only in real life, not here ]
Draw an imaginary line from initial position to final position.
Now, In that triangle, tan x = P/B
tan x = 1.4 / 2
tan x = 0.70
x = tan⁻¹ (0.70)
x = 35 [ tan 35 = 0.70 ]
In short, Your Answer would be 35 degrees
Hope this helps!
In order for a system to be in equilibrium , two conditions must be met. Net force must be 0.
A) an object with mass > 0 in a gravitational field
b) an object with an electric charge not 0 in an electric field
c) a moving object with an electric charge not 0 in a magnetic field
Answer:
Work to move on ion inside a cell = 1.168×10^-20J
Explanation:
Potential difference is a ratio of work done by a charge.
It is given as
◇V= Workdone ×charge= W/a
Workdone = V × q= (7.3×10^-2)×(1.6×10^-19)
W= 1.168×10^-20Joules
