Question

Buster Posey hits a pop-up straight up. The velocity of the baseball as it leaves the bat is 42.5 m/s. Determine (a) the total time the baseball is in the air, and (b) the maximum height the baseball reaches. Assume the baseball is caught at the same height above the ground as it was hit. Draw an image of the baseball for each 1 second of time it is traveling, for each image include a labeled velocity and acceleration vector.

Answer 1

Answer:

part a: 4.25s

part b: 180.625m

Explanation:

part a:

what we know: vi=42.5m/s

                          t=?

                          vf=0

                          g= -10m/s^2

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equation: vf-vi/g=t

plug in: -42.5m/s/ - 10m/s^2 = 4.25s

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part b: 42.5m/s x(times) 4.25s = 180.625m