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OverLord2011 [107]
3 years ago
5

A=(vf-vi)/t d= Vi x t + at2/2 d=(vf2-vi2)/2a d=((Vi+vf)/2) t

Physics
1 answer:
Liula [17]3 years ago
5 0

Answer:

I wasn't sure what you really need so i listed all of them if they are not what you are looking for please tell me for me to correct it.Hope this help ;)

Explanation:

VF VI t mean

a= Vf - Vi /t. acceleration = final velocity - initial velocity divided by time.

d= Vi x t + at2/2 The final velocity is zero

the last two i couldn't solve but i will try my best to finish those.

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What would be the magnitude of the electric field 0.75 m from a 0.63 C master charge and what would be the force on a 0.50 C tes
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The magnitude of the electric field on the master charge is 1.008 x 10¹⁰ N/C, and the force on the test charge is 5.04 x 10⁹ N.

<h3>Electric field on the master charge</h3>

E = kq/r²

where;

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E = (9 x 10⁹ x 0.63)/(0.75²)

E = 1.008 x 10¹⁰ N/C

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F = Eq

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F = (1.008 x 10¹⁰) x (0.5)

F = 5.04 x 10⁹ N

Thus, the magnitude of the electric field on the master charge is 1.008 x 10¹⁰ N/C, and the force on the test charge is 5.04 x 10⁹ N.

Learn more about electric field here: brainly.com/question/14372859

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