The answer is 6.4109 grams
Answer:
All bonds are equivalent in length and strength within the molecule.
Gaseous SO3 is a trigonal planar molecule that exhibit a D3h symmetry group.
Sulfur has sp2 hybridization and it has 6 outer electrons which make the bonds with the oxygen.
Its constituent sulfur atom has an oxidation state of +6 and a formal charge of 0.
The Lewis structure is made up of one S=O double bond and two S–O dative bonds that doesn't not engage the d-orbitals. ( Thus, SO3 molecule has three double bonded oxygen to the central sulfur atom). This explains the strength.
It gaseous form had a zero electrical dipole moment because of the 120° angle between the S-O bonds.
Explanation:
Respuesta:
2 FeCl₃(aq) + 3 Na₂CO₃(s) ⇒ Fe₂(CO₃)₃(s) + 6 NaCl(aq)
Explicación:
Consideremos la ecuación no balanceada que ocurre cuando cloruro férrico acuoso reacciona con carbonato de sodio sólido para formar carbonato férrico sólido y cloruro de sodio acuoso. Esta es una reacción de doble desplazamiento.
FeCl₃(aq) + Na₂CO₃(s) ⇒ Fe₂(CO₃)₃(s) + NaCl(aq)
Vamos a usar el método de tanteo. Empezaremos balanceando los átomos de C, multiplicando Na₂CO₃ por 3.
FeCl₃(aq) + 3 Na₂CO₃(s) ⇒ Fe₂(CO₃)₃(s) + NaCl(aq)
Luego, balancearemos los átomos de Fe, multiplicando FeCl₃ por 2.
2 FeCl₃(aq) + 3 Na₂CO₃(s) ⇒ Fe₂(CO₃)₃(s) + NaCl(aq)
Finalmente, obtendremos la ecuación balanceada, multiplicando NaCl por 6.
2 FeCl₃(aq) + 3 Na₂CO₃(s) ⇒ Fe₂(CO₃)₃(s) + 6 NaCl(aq)
The rule that we will use to solve this problem is:
M2*V1 = M2*V2 where:
M1 is the initial concentration = 3.5 m
V1 is the initial volume = 0.25 l = 250 ml
M2 is the final concentration = 9 m
V2 is the final volume that we need to find
Substitute with the givens in the above equation to get V2 as follows:
3.5*250 = 9*V2
V2 = 97.2223 ml
